awamy wrote:

the roots of the equation x^2+3x-10=0. where α<β, an equation whose roots are α-1 and β+2 is?

The question is not clear. Are α, β roots of \(x^2+3x-10=0\)? If so...

\(x^2+3x-10=0\) or \((x + 5)(x - 2)=0\) so α=-5 or β=2 ..... as α<β.

So α-1= -6 and β+2=4.

Hence the new equation \((x + 6)(x - 4)=0\) or \(x^2+ 2x - 24 =0\)

_________________

Sandy

If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test