sandy wrote:

Water flows into a 25-liter bucket through a hose and out through a hole in the bottom of the bucket. The rate of flow through the hose is 1 liter per minute. If the bucket is filled to capacity in 40 minutes, at what rate, in liters per minute, was water flowing out of the bucket through the hole?

A. \(\frac{3}{8}\)

B. \(\frac{3}{5}\)

C. \(\frac{5}{8}\)

D. \(\frac{8}{5}\)

E. \(\frac{13}{8}\)

Drill 2

Question: 7

Page: 525

We can solve the problem using the equation

A = R x T

Where A= 25 L

R (Total) = R (inlet) - R (outlet) (Since we have rate of water entering the bucket and the rate of water flowing out the bucket)

R (inlet) = 1 Litre/minute

R (outlet) = Let us assume as r Litre/minute

T = 40 minute

Therefore we have

25 = (1 - r) X 40

or \(\frac{25}{40}\)= 1 - r

or r = 1 - \(\frac{5}{8}\)

or r =\(\frac{3}{8}\)

Hence the rate at which the the water was flowing out is = \(\frac{3}{8}\)

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