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# Water flows into a 25-liter bucket through a hose and out

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GRE Prep Club Legend
Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Water flows into a 25-liter bucket through a hose and out [#permalink]  24 Nov 2017, 20:56
Expert's post
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Question Stats:

71% (02:36) correct 28% (00:50) wrong based on 7 sessions
Water flows into a 25-liter bucket through a hose and out through a hole in the bottom of the bucket. The rate of flow through the hose is 1 liter per minute. If the bucket is filled to capacity in 40 minutes, at what rate, in liters per minute, was water flowing out of the bucket through the hole?

A. $$\frac{3}{8}$$
B. $$\frac{3}{5}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
E. $$\frac{13}{8}$$

Drill 2
Question: 7
Page: 525
[Reveal] Spoiler: OA

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Sandy
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Joined: 20 Apr 2016
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Re: Water flows into a 25-liter bucket through a hose and out [#permalink]  01 Dec 2017, 08:51
1
KUDOS
sandy wrote:
Water flows into a 25-liter bucket through a hose and out through a hole in the bottom of the bucket. The rate of flow through the hose is 1 liter per minute. If the bucket is filled to capacity in 40 minutes, at what rate, in liters per minute, was water flowing out of the bucket through the hole?

A. $$\frac{3}{8}$$
B. $$\frac{3}{5}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
E. $$\frac{13}{8}$$

Drill 2
Question: 7
Page: 525

We can solve the problem using the equation

A = R x T

Where A= 25 L

R (Total) = R (inlet) - R (outlet) (Since we have rate of water entering the bucket and the rate of water flowing out the bucket)

R (inlet) = 1 Litre/minute
R (outlet) = Let us assume as r Litre/minute

T = 40 minute

Therefore we have

25 = (1 - r) X 40

or $$\frac{25}{40}$$= 1 - r

or r = 1 - $$\frac{5}{8}$$

or r =$$\frac{3}{8}$$

Hence the rate at which the the water was flowing out is = $$\frac{3}{8}$$
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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4856
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 102

Kudos [?]: 1742 [0], given: 397

Re: Water flows into a 25-liter bucket through a hose and out [#permalink]  29 Dec 2017, 13:59
Expert's post
Explanation

Remember that amount = rate × time. So, 25 liters = rate × 40 minutes.

The rate was $$\frac{25}{40}=\frac{5}{8}$$ liters/min.

The net rate at which the bucket is filling is the difference between the hose’s rate and the leaking rate. So, (1 liter/min) – (leaking rate) = $$\frac{5}{8}$$.

Solve for the leaking rate to find the leaking rate is $$\frac{3}{8}$$liters/min; the answer is choice A.
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Sandy
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Re: Water flows into a 25-liter bucket through a hose and out   [#permalink] 29 Dec 2017, 13:59
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