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Victor is walking at a rate of 1 mile every 17 minutes

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GMAT Club Legend
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Joined: 07 Jun 2014
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Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 09 Dec 2017, 18:51
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100% (02:54) correct 0% (00:00) wrong based on 3 sessions
Victor is walking at a rate of 1 mile every 17 minutes. Sarah is walking at a rate of 1 mile every 14 minutes. If they are 10 miles apart and are approaching each other along a straight road, how many hours will it take them to meet, rounded to the nearest hundredth?

Drill 2
Question: 11
Page: 533


[Reveal] Spoiler: OA
1.28

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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 10 Dec 2017, 05:56
Hi Sandy,

thanks for posting the question.

However my answer is far from 10. I dont know what i am doing wrong here.

Rate of Viktor= 60/17 m/h
Rate of Sarah = 60/14 m/h

Adding the variable T and setting them equal to 10 gives me 1.3 hours.
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 10 Dec 2017, 15:26
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Hi sandy,


My answer is also not 10.how it is possible?
my explanation is that,both of them together can cover 2.21 miles in every 17 minutes(for victor 1 miles in 17 minutes and for saraha approximately 1.21 miles in 17 minutes([1/14]*17=1.21)).
therefore both of them together can cover 10 miles in 76.92 minutes=1.28 hr=1.3 hr
or in another words both of them took 1.3 hr to meet each other
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 10 Dec 2017, 16:55
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My bad guys! Answer is 1.28. Changed it!

Thanks for pointing out!
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Sandy
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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1650 [0], given: 396

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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 29 Dec 2017, 16:46
Expert's post
Explanation

First, find the two people’s rates in terms of miles per hour (mph). Victor’s rate equals distance over time, or 1 mile over \(\frac{17}{60}\)hours, which equals approximately 3.529 mph.

Calculating Sarah’s speed using the same steps gives you her rate, 4.286 mph. When added, the two rates become their combined rate of 7.815 mph. When you divide 10 miles by 7.815, the answer is approximately 1.28 hours until they meet.
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink] New post 23 Jan 2018, 11:37
s1=1/17
s2=1/14
t=10/(1/17+1/14)
=2380/31
=1.279
=1.28
Re: Victor is walking at a rate of 1 mile every 17 minutes   [#permalink] 23 Jan 2018, 11:37
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Victor is walking at a rate of 1 mile every 17 minutes

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