ExplanationCall the race times x and y. The question provides a sum: x + y = 170.

One of the race times is 10 seconds less than twice the other: x = 2y – 10.

Since the second equation is already solved for x, plug (2y – 10) in for x in the first equation:

\(2y - 10 + y = 170\)

\(3y - 10 = 170\)

\(3y = 180\)

\(y = 60\)

If y = 60 and the times sum to 170, then x = 110.

Note that the question asks for the faster race time—that means the smaller number! The answer is 60.

Hence option C is correct!
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Sandy

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