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# Two people were hired to mow a lawn for a total of $45. They  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Founder Joined: 18 Apr 2015 Posts: 8139 Followers: 157 Kudos [?]: 1710 [0], given: 7485 Two people were hired to mow a lawn for a total of$45. They [#permalink]  03 Sep 2019, 10:06
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Question Stats:

66% (00:01) correct 33% (00:13) wrong based on 3 sessions
Two people were hired to mow a lawn for a total of $45. They completed the job with one person working for 1 hour and 20 minutes and the other working 40 minutes. If they split the$45 in proportion to the amount of time each spent working on the job, how much did the person who worked longer receive?

(A) $33.75 (B)$30.00

(C) $27.50 (D)$25.00

(E) $22.50 [Reveal] Spoiler: OA _________________ VP Joined: 20 Apr 2016 Posts: 1002 WE: Engineering (Energy and Utilities) Followers: 14 Kudos [?]: 796 [1] , given: 176 Re: Two people were hired to mow a lawn for a total of$45. They [#permalink]  07 Sep 2019, 19:28
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Carcass wrote:
Two people were hired to mow a lawn for a total of $45. They completed the job with one person working for 1 hour and 20 minutes and the other working 40 minutes. If they split the$45 in proportion to the amount of time each spent working on the job, how much did the person who worked longer receive?

(A) $33.75 (B)$30.00

(C) $27.50 (D)$25.00

(E) $22.50 Let's convert hours to min; 1 hour 20 min = 80 mins Total time spent by the 2 people = 120 mins Total payment received =$45

Therefore, the person working for 80 mins receive = $$\frac{45}{120} *80$$= $30 and the person working for 40 mins receive = $$\frac{45}{120} *40$$=$15
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