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# Twelve runners enter a race to compete for first, second, an

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GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4647
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 85

Kudos [?]: 1549 [0], given: 365

Twelve runners enter a race to compete for first, second, an [#permalink]  30 Dec 2017, 14:30
Expert's post
00:00

Question Stats:

100% (00:13) correct 0% (00:00) wrong based on 1 sessions
Twelve runners enter a race to compete for first, second, and third place. How many different combinations of winners are possible?

Drill 2
Question: 10
Page: 564

[Reveal] Spoiler: OA
1320

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Sandy
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GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4647
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 85

Kudos [?]: 1549 [0], given: 365

Re: Twelve runners enter a race to compete for first, second, an [#permalink]  12 Jan 2018, 15:28
Expert's post
Explanation

In this case, order matters, so you simply need to multiply the number of possible runners for each spot. That should look like this: $$12 \times 11 \times 10 = 1,320$$.
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Sandy
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Re: Twelve runners enter a race to compete for first, second, an   [#permalink] 12 Jan 2018, 15:28
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