Carcass wrote:
Triangular region T1 and T2 have equal areas and have heights h1 and h2 respectively
Quantity A |
Quantity B |
(area of T1)/h1 |
(area of T2)/h2 |
Another approach is to look at different cases.
Area of a triangle = (base)(height)/2
case 1:
T1 has base of 4 and a height (h1) of 4
T2 has base of 4 and a height (h2) of 4
Area of T1 = (4)(4)/2 = 8
Area of T2 = (4)(4)/2 = 8
As you can see the two triangles have the same area.
We get:
Quantity A: (area of T1)/h1 = 8/4 = 2
Quantity B: (area of T2)/h2 = 8/4 = 2
In this case, the
the two quantities are equalcase 2:
T1 has base of 4 and a height (h1) of 3
T2 has base of 3 and a height (h2) of 4
Area of T1 = (4)(3)/2 = 6
Area of T2 = (3)(4)/2 = 6
As you can see the two triangles have the same area.
We get:
Quantity A: (area of T1)/h1 = 6/3 = 2
Quantity B: (area of T2)/h2 = 6/4 = 1.5
In this case, the
quantity A is greaterAnswer: D
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Brent Hanneson – Creator of greenlighttestprep.com
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