chetan2u wrote:

AE wrote:

chetan2u wrote:

Now this is <12 so 30 is more than RST

B>A

Is this correct?

Yes, it is correct...

\(6\sqrt{3}<6\sqrt{4}................6\sqrt{3}<6*2................6\sqrt{3}<12\)

ohhh! I was confused with the word 'this is', I thought something else in relation to angle.

I think I am clear now.

If angle=30 y=6 x=6[/square_root]3[square_root]

as x=12 that is x>12 angle must be less than 30 to commiserate with the other contents of the right triangle.

Thanks for your reply

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Please let me know if I am wrong.