GreenlightTestPrep wrote:

If x > 0, b > a, and 2x + 5 < 3x + 1, then which of the following COULD be a value of x?

i) 4.39

ii) 7.17

iii) 9.27

A) i and ii only

B) ii and iii only

C) i and iii only

D) iii only

E) i, ii and iii

Here's a useful triangle property:

So, if b > a, then we know that 3x + 1 < 4x - 8

We're also told that 2x + 5 < 3x + 1

So, we can create the following 3-part inequality: 2x + 5 < 3x + 1 < 4x - 8

Subtract 2x from all 3 sides: 5 < x + 1 < 2x - 8

When we examine 5 < x + 1, we can conclude that 4 < x. So, x is greater than 4

When we examine x + 1 < 2x - 8, we can conclude that 9 < x. So, x is greater than 9

So, we know that x is greater than 4 AND x is greater than 9

So, it MUST be the case that

x is greater than 9Check the statements.....

Only statement iii works.

Answer: D

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

Sign up for our free GRE Question of the Day emails