GreenlightTestPrep wrote:

P = the product of

all x-values that satisfy the equation (x²)^(x² - 2x + 1) = x^(3x² + x + 8)

What is the value of P?

Answer:

IMPORTANT: If b^x = b^y, then x = y, as long as b ≠ 0, b ≠ 1 and b ≠ -1For example, if we have 1^x = 1^y, we cannot conclude that x = y, since 1^x equals 1^y FOR ALL values of x and y.

So, although 1² = 1³, we can't then conclude that 2 = 3.

So, let's first see what happens when the base (x) equals 0.

If x =

0, then we get: (

0²)^(

0² - 2

(0) + 1) =

0^(3

(0²) +

0 + 8)

Simplify: 0^1 = 0^8

Evaluate: 0 = 0

Perfect! We know that x =

0 is one solution to the equation.

This means the PRODUCT of all of the solutions will be ZERO, regardless of the other solutions.

In other words, P = 0

Answer: 0

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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