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To the nearest percent, by what percent did the population o [#permalink]
 22 May 2017, 01:05
Question Stats:
23% (02:38) correct
76% (02:16) wrong based on 30 sessions
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Re: To the nearest percent, by what percent did the population o [#permalink]
24 Sep 2017, 20:52
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Founder
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Re: To the nearest percent, by what percent did the population o [#permalink]
25 Sep 2017, 02:38
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Re: To the nearest percent, by what percent did the population o [#permalink]
01 Jul 2018, 10:05
Carcass wrote: Please post your answer as text and your resoning. We solve together.
Do not post a screen.
Thank you I agree Carcass, but why he assumed it was 1000 stolen vehicles? And why he assumed that the population must be increased?
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Re: To the nearest percent, by what percent did the population o [#permalink]
01 Jul 2018, 10:32
The solution posted is partial, missing the last key sentence. Quote: Simplify the situation by assuming that in 1994 the population was 100,000 and there were 1000 vehicles stolen.The number of thefts per 100,000 inhabitants decreased 22.4% from 1000 to 776. So if there were 776 vehicles stolen for every 100,000 inhabitants, and 806 cars were stolen, the number of inhabitants must have increased. To know by how much, solve the proportion: \(\frac{776}{100,000}\) = \(\frac{806}{x}\) Cross-multiplying, we get \(776x = 80,600,000\). So, \(x = 103,800\). Then for every 100,000 inhabitants in 1994, there were 103,800 in 1998, an increase of \(3.8%\).
Ask for further assistance. Regards
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Re: To the nearest percent, by what percent did the population o [#permalink]
02 Jul 2018, 00:17
Carcass wrote: The solution posted is partial, missing the last key sentence. Quote: Simplify the situation by assuming that in 1994 the population was 100,000 and there were 1000 vehicles stolen. The number of thefts per 100,000 inhabitants decreased 22.4% from 1000 to 776. So if there were 776 vehicles stolen for every 100,000 inhabitants, and 806 cars were stolen, the number of inhabitants must have increased. To know by how much, solve the proportion: \(\frac{776}{100,000}\) = \(\frac{806}{x}\) Cross-multiplying, we get \(776x = 80,600,000\). So, \(x = 103,800\). Then for every 100,000 inhabitants in 1994, there were 103,800 in 1998, an increase of \(3.8%\).
Ask for further assistance. Regards I have got the general paradigm for solving this question as you can assume the initial number of stolen cars to be any number from 100 to 1 billion, but you will always get the same ratio always. But the logic of combining everything altogether and assuming that it increased is still vague to me.
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Re: To the nearest percent, by what percent did the population o [#permalink]
02 Jul 2018, 15:25
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Re: To the nearest percent, by what percent did the population o [#permalink]
07 Aug 2018, 00:34
Is the question incomplete? There are no numbers to being with. How are assuming how many cars were stolen? How do we know 806 cars were stolen? i am so lost. Is this from an actual test?
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Re: To the nearest percent, by what percent did the population o [#permalink]
07 Aug 2018, 01:05
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Re: To the nearest percent, by what percent did the population o [#permalink]
09 Aug 2019, 19:22
carcass please the explain the question using other solution other than that is mentioned above
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Re: To the nearest percent, by what percent did the population o [#permalink]
10 Aug 2019, 11:54
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Re: To the nearest percent, by what percent did the population o [#permalink]
16 Aug 2019, 07:11
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Is there missing any info ?
I think, enough data is not exist here.
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close
