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Three tennis balls of identical size are [#permalink]
Expert's post 00:00

Question Stats: 94% (00:52) correct 5% (00:24) wrong based on 18 sessions
Attachment: #GREpracticequestion Three tennis balls of identical size are stacked.jpg [ 3.51 KiB | Viewed 121 times ]

Three tennis balls of identical size are stacked one on top of the other so that they fit exactly inside a closed right cylindrical can, as shown.

 Quantity A Quantity B The height of the stack of 3 balls The circumference of one of the balls

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ GRE Instructor Joined: 10 Apr 2015
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Re: Three tennis balls [#permalink]
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Expert's post
Carcass wrote:
Attachment:
tennis.jpg

Three tennis balls of identical size are stacked one on top of the other so that they fit exactly inside a closed right cylindrical can, as shown.

 Quantity A Quantity B The height of the stack of 3 balls The circumference of one of the balls

Let's examine Quantity A first

Let r = the radius of a tennis ball This means the HEIGHT of one tennis ball = r + r = 2r So, the height of the can = r + r + r + r + r + r = 6r

So, Quantity A = 6r

-----------------------------------
Now let's deal with Quantity B The circumference of a ball with radius r = the circumference of a circle with radius r
The circumference of a circle = 2πr
So, Quantity B = 2πr

-----------------------------------
We have:
Quantity A: 6r
Quantity B: 2πr

Since π ≈ 3.14, we know that 2π ≈ 6.28

So, we have:
Quantity A: 6r
Quantity B: 6.28r

We can see that Quantity B is greater.

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com Sign up for our free GRE Question of the Day emails

Moderator  Joined: 18 Apr 2015
Posts: 5897
Followers: 96

Kudos [?]: 1154 , given: 5479

Re: Three tennis balls [#permalink]
Expert's post
GREAT explanation Sir.

Regards
_________________ GRE Instructor Joined: 10 Apr 2015
Posts: 1543
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Kudos [?]: 1468  , given: 8

Re: Three tennis balls [#permalink]
1
KUDOS
Expert's post
Carcass wrote:
GREAT explanation Sir.

Regards

Thanks!!!
_________________

Brent Hanneson – Creator of greenlighttestprep.com Sign up for our free GRE Question of the Day emails Director Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Re: Three tennis balls [#permalink]
1
KUDOS
Carcass wrote:
Attachment:
tennis.jpg

Three tennis balls of identical size are stacked one on top of the other so that they fit exactly inside a closed right cylindrical can, as shown.

 Quantity A Quantity B The height of the stack of 3 balls The circumference of one of the balls

Here,

Lets take diameter of the 1 tennis ball = 10 cm

so radius of the 1 tennis ball = 5 cm

Now QTY A;

Height of 3 tennis ball = 10 + 10 + 10 = 30 cm (i.e. the sum of the diameter of the tennis ball will give the total height)

Now QTY B

Circumference of 1 tennis ball = 2 * \pi * Radius = 2 * 3.14 * 5 = 31.4

Hence QTY A > QTY B.

**The diameter can be any value, for easy calculation 10 is assumed.
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Re: Three tennis balls   [#permalink] 06 Jul 2018, 06:12
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