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# The volume V of a right circular cylinder is V = πr2h, where

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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The volume V of a right circular cylinder is V = πr2h, where [#permalink]  01 Jun 2016, 16:54
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Question Stats:

92% (00:53) correct 7% (01:20) wrong based on 13 sessions
The volume V of a right circular cylinder is $$V = \pi$$$$r^2h$$, where r is the radius of the base and h is the height of the cylinder. If the volume of a right circular cylinder is $$45\pi$$ and its height is 5, what is the circumference of its base?

A. $$3$$

B. $$9$$

C. $$3\pi$$

D. $$6\pi$$

E. $$9\pi$$

Practice Questions
Question: 8
Page: 101
[Reveal] Spoiler: OA

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 123

Kudos [?]: 1975 [0], given: 397

Re: The volume V of a right circular cylinder is V = πr2h, where [#permalink]  01 Jun 2016, 16:58
Expert's post
Explanation

You are given that the volume of the right circular cylinder is 45π and the height is 5. It follows that π$$r^2h$$ = 45π, or $$r^2h$$ = 45. Since h = 5 and $$r^2h$$ = 45, it follows that $$r^2$$ = 9, or r = 3. Therefore the circumference of the circular base is 2πr = 2π (3) = 6π, and the correct answer is Choice D.
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Sandy
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Re: The volume V of a right circular cylinder is V = πr2h, where   [#permalink] 01 Jun 2016, 16:58
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# The volume V of a right circular cylinder is V = πr2h, where

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