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# The total stopping distance for the car traveling at 60 mile

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The total stopping distance for the car traveling at 60 mile [#permalink]  19 Jan 2016, 15:00
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62% (01:08) correct 37% (01:33) wrong based on 75 sessions
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#GREpracticequestion The total stopping distance for the car traveling at 60 miles.jpg [ 154.54 KiB | Viewed 3644 times ]

The total stopping distance for the car traveling at 60 miles per hour is approximately what percent greater than the total stopping distance for the car traveling at 50 miles per hour?

A. 22%

B. 30%

C. 38%

D. 45%

E. 52%

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[Reveal] Spoiler: OA

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Founder
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Kudos [?]: 2986 [0], given: 11220

Re: The total stopping distance for the car traveling at 60 mile [#permalink]  19 Jan 2016, 15:09
Expert's post
Solution

The question seems at glance convoluted but is a simple % change. A ratio, actually

Using both graphs, you do need to find the total stopping distance at 50 miles per hour and at 60 miles per hour, find their difference, and then express the difference as a percent of the shorter total stopping distance. At 50 miles per hour, the total stopping distance is approximately 55+137=192 feet; and at 60 miles per hour it is approximately 66+198=264 feet. The difference of 72 feet as a percent of 192 feet is $$\frac{72}{192}=0.37$$ or approximately 38%.

The correct answer is $$C.$$
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Re: The total stopping distance for the car traveling at 60 mile [#permalink]  23 Dec 2019, 07:15
Sometimes it is not obvious that the task includes percentage change))
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Re: The total stopping distance for the car traveling at 60 mile [#permalink]  06 May 2020, 10:17
gulsam wrote:
Sometimes it is not obvious that the task includes percentage change))

"What percent greater" this is the indication that questions is asking for percentage change

At 50 mph: 55 + 137 = 192
At 60 mph: 66 + 198 = 264

percent change = new - old / old
= 264 - 192 / 192
= approx 38
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Re: The total stopping distance for the car traveling at 60 mile   [#permalink] 06 May 2020, 10:17
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