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The total downhill distance traveled by a skier moving at 20

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The total downhill distance traveled by a skier moving at 20 [#permalink] New post 05 Aug 2018, 02:38
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The total downhill distance traveled by a skier moving at 20 mph, from the moment he spots the boulder until he successfully veers 10 feet to his right, is approximately what percent smaller than the total downhill distance traveled by a skier in the same situation who is moving at 50 mph?

A. 23

B. 35

C. 60

D. 77

E. 80
[Reveal] Spoiler: OA

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Re: The total downhill distance traveled by a skier moving at 20 [#permalink] New post 11 Aug 2018, 11:25
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Several steps involved here.

We need to:

Calculate the distance traveled during reaction time and veering time for skier traveling 20mph.

Calculate the distance traveled during reaction time and veering time for skier traveling 50mph.

Divide the total distance traveled during reaction time and veering time for skier traveling 20mph by total distance traveled for skier traveling 50mph.

Realize that the question asks "what percent smaller" the distance for 20mph skier is, so the answer for our first calculation (23%) is not the answer to the question. The 20mph skier travels 23% of the distance of the 50mph skier, so the 20mph skier travels 77% smaller distance than the 50mph skier.

So the answer is D.
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Re: The total downhill distance traveled by a skier moving at 20 [#permalink] New post 08 Sep 2018, 15:11
Someone please explain this? I don't understand the graphs or the question
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Re: The total downhill distance traveled by a skier moving at 20 [#permalink] New post 09 Sep 2018, 16:34
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The definition at the bottom of the graph says: The total downhill (or downward is the same thing, actually) is the same of the distance given in the first graph and that in the second graph.

Now, for a skier at 20 mph during his reaction time is 15 (from the first graph) and at 20 mph is 50 (in the second graph. So, the total is 65 feet.

The same you have to sum for the second skier which is a total distance of 285.

Now, the difference in % of the two distances is \(\frac{65}{285}\) \(\approx 0.23\)

But the question ask for approximately what percent smaller than.

So this means that on a total distance of 100 you have to subtract 0.23 which is 77%.

D is the answer.

Attachment:
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hill.jpg [ 56.68 KiB | Viewed 171 times ]

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