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# The table above shows the frequency distribution of the valu

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The table above shows the frequency distribution of the valu [#permalink]  04 Jan 2016, 08:56
Expert's post
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Array[ATTACHMENT]:

#GREpracticequestion The table above shows the frequency distribution.jpg [ 22.99 KiB | Viewed 1558 times ]

The table above shows the frequency distribution of the values of a variable Y. What is the mean of the distribution?

[Reveal] Spoiler: OA
1.29

Practice Questions
Question: 13
Page: 159
Difficulty: hard

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Sandy
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Retired Moderator
Joined: 07 Jun 2014
Posts: 4808
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 145

Kudos [?]: 2263 [0], given: 393

Re: frequency distribution of the values of a variable Y [#permalink]  04 Jan 2016, 15:56
Expert's post
Now we have here is a frequency distribution table. There is no short cut so we sum the values i.e.

Sum = Y * frequency = $$\frac{1}{2}*2 +\frac{3}{4}*7 + \frac{5}{4}*8 + \frac{6}{4}*8 + \frac{7}{4}*9$$ =44

Number of terms = sum of all the frequency = 34

Mean = 44/34 = 1.29.
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Re: frequency distribution of the values of a variable Y [#permalink]  13 Jul 2016, 14:37
sandy Array[WROTE]:
Now we have here is a frequency distribution table. There is no short cut so we sum the values i.e.

Sum = Y * frequency = $$\frac{1}{2}*2 +\frac{3}{4}*7 + \frac{5}{4}*8 +\frac{3}{2}*8 + \frac{5}{4}*8 + \frac{7}{4}*9$$ =44

Number of terms = sum of all the frequency = 34

Mean = 44/34 = 1.29.

You have an extra term in the sum. Only one 5/4*8.
Retired Moderator
Joined: 07 Jun 2014
Posts: 4808
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 145

Kudos [?]: 2263 [0], given: 393

Re: frequency distribution of the values of a variable Y [#permalink]  13 Jul 2016, 17:45
Expert's post
jl15769n Array[WROTE]:

You have an extra term in the sum. Only one 5/4*8.

It was supposed to be $$\frac{6}{4}$$, it was a type. Fixed it

Thanks and Regards,
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Re: frequency distribution of the values of a variable Y [#permalink]  24 May 2019, 16:20
Expert's post
sandy Array[WROTE]:

 Y Frequency $$\frac{1}{2}$$ 2 $$\frac{3}{4}$$ 7 $$\frac{5}{4}$$ 8 $$\frac{3}{2}$$ 8 $$\frac{7}{4}$$ 9

The table above shows the frequency distribution of the values of a variable Y. What is the mean of the distribution?

[Reveal] Spoiler: OA
1.29

Practice Questions
Question: 13
Page: 159
Difficulty: hard

The table tells us that the distribution contains TWO 1/2's, SEVEN 3/4's, EIGHT 5/4's etc

To find mean, we must first find the sum of all of the values in the distribution.

SUM = (2)(1/2) + (7)(3/4) + (8)(5/4) + (8)(3/2) + (9)(7/4)
= 1 + 21/4 + 10 + 12 + 63/4
= 23 + 21/4 + 63/4
= 23 + 84/4
= 23 + 21
= 44

The NUMBER of values in the distribution = 2 + 7 + 8 + 8 + 9
= 34

So, the mean = 44/34 = 1.294....

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

Re: frequency distribution of the values of a variable Y   [#permalink] 24 May 2019, 16:20
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