sandy wrote:
| Y | Frequency |
| \(\frac{1}{2}\) | 2 |
| \(\frac{3}{4}\) | 7 |
| \(\frac{5}{4}\) | 8 |
| \(\frac{3}{2}\) | 8 |
| \(\frac{7}{4}\) | 9 |
The table above shows the frequency distribution of the values of a variable Y. What is the mean of the distribution?
Give your answer to the nearest 0.01.Practice Questions
Question: 13
Page: 159
Difficulty: hard
The table tells us that the distribution contains TWO 1/2's, SEVEN 3/4's, EIGHT 5/4's etc
To find mean, we must first find the
sum of all of the values in the distribution.
SUM = (2)(1/2) + (7)(3/4) + (8)(5/4) + (8)(3/2) + (9)(7/4)
= 1 + 21/4 + 10 + 12 + 63/4
= 23 +
21/4 + 63/4= 23 +
84/4= 23 +
21= 44
The NUMBER of values in the distribution = 2 + 7 + 8 + 8 + 9
= 34
So, the mean = 44/34 = 1.294....
Answer: 1.29
Cheers,
Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com
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81% (01:47) correct
