Now we have here is a frequency distribution table. There is no short cut so we sum the values i.e.

Sum = Y * frequency = \(\frac{1}{2}*2 +\frac{3}{4}*7 + \frac{5}{4}*8 + \frac{6}{4}*8 + \frac{7}{4}*9\) =44


Number of terms = sum of all the frequency = 34


Mean = 44/34 = 1.29.
_________________

You have an extra term in the sum. Only one 5/4*8.

It was supposed to be \(\frac{6}{4}\), it was a type. Fixed it


Thanks and Regards,
_________________

The table tells us that the distribution contains TWO 1/2's, SEVEN 3/4's, EIGHT 5/4's etc

To find mean, we must first find the sum of all of the values in the distribution.

SUM = (2)(1/2) + (7)(3/4) + (8)(5/4) + (8)(3/2) + (9)(7/4)
= 1 + 21/4 + 10 + 12 + 63/4
= 23 + 21/4 + 63/4
= 23 + 84/4
= 23 + 21
= 44

The NUMBER of values in the distribution = 2 + 7 + 8 + 8 + 9
= 34

So, the mean = 44/34 = 1.294....

Answer: 1.29

Cheers,
Brent
_________________

Bump
_________________

I always get confused while calculating the mean and median of a given frequency distribution table. Any good article to go through this concept?