Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Working in collaboration with examPAL we will provide you with a unique online learning experience which will help you reach that higher score. Start your free 7 day trial today.

LEARN WITH AN EXPERT TEACHER—FOR FREE - Take a free practice test, learn content with one of our highest-rated teachers, or challenge yourself with a GRE Workshop.

An overview of and discussion about the GRE argument essay. The first 20 minutes of this webinar will consist of a “presentation” on a specific topic, and the last 40 minutes consists of live Q&A covering pre-submitted or live questions.

This admissions guide will help you plan your best route to a PhD by helping you choose the best programs your goals, secure strong letters of recommendation, strengthen your candidacy, and apply successfully.

The sum of the odd/even integers [#permalink]
20 Jan 2016, 18:36

1

This post received KUDOS

Expert's post

00:00

Question Stats:

63% (01:01) correct
36% (00:45) wrong based on 141 sessions

Quantity A

Quantity B

The sum of the odd integers from 1 to 199

The sum of the even integers from 2 to 198

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Practice Questions Question: 7 Page: 458 Difficulty: medium

Re: The sum of the odd/even integers [#permalink]
22 Jan 2016, 07:45

Expert's post

Solution

The most straightforward way to solve this question, among the others, is to count the numbers in the sets

From quantity \(A\) we do have that

\(199+1=\frac{200}{2}=100\) So we have the precise middle of the set, the average

Then count the numbers in the set \(199-1=\frac{198}{2}=99+1=100\) (we divide by two because we want only the odd numbers, one yes one no)

Multiply \(100*100=10000\)

Same for quantity \(B\)

\(198+2=\frac{200}{2}=100\)

\(198-2=\frac{196}{2}=98+1=99\)

\(99*100=9900\)

\(A > B\)

The answer is\(A\)

Note: if we were in GMAT Land the question would specify that the numbers at the extreme of the set are inclusive or not. Here, we assume that they are inclusive.
_________________

Re: The sum of the odd/even integers [#permalink]
27 Apr 2016, 08:42

1

This post received KUDOS

Let’s fit the range in between any of them. The odd integers from 1 to 199 can be placed between the range of even integers from 2 to 198 or vice versa.

If the range swallows other range, the sum of the numbers of swallowing range must be greater than that of swallowed range. For example, 1, 2, 3,…………..8 or 2,3,,,,,,,,,,,,7.Sum of all numbers in the first range must be greater than that of 2nd range.

Brent Hanneson – Creator of greenlighttestprep.com If you enjoy my solutions, you'll like my GRE prep course. Sign up for GRE Question of the Dayemails

Re: The sum of the odd/even integers [#permalink]
20 Sep 2017, 08:17

1

This post received KUDOS

Probably less fast than Carcass answer but we can also see that what we are asked is the sum of an arithmetic progression that is equal to \(S_n=\frac{n}{2}(f+l)\) where n is the number of elements of our progression, f is the first element and l is the last one. Applying this rule to the column A we would get that n = 100 since 199/2=99.5 but the list terminates with an odd number. Thus the formula becomes \(\frac{100}{2}(1+199)=10,000\). Using the same rationale for column B, we get that B = 9,900. Thus, A is larger!

Re: The sum of the odd/even integers [#permalink]
18 May 2018, 08:51

2

This post received KUDOS

Expert's post

sandy wrote:

Quantity A

Quantity B

The sum of the odd integers from 1 to 199

The sum of the even integers from 2 to 198

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Compare the 1st number in each quantity (1 and 2). At this point in the sums, Quantity B is 1 greater than Quantity A. Compare the 2nd number in each quantity (3 and 4). At this point in the sums, Quantity B is 2 greater than Quantity A. Compare the 3rd number in each quantity (5 and 6). At this point in the sums, Quantity B is 3 greater than Quantity A. Compare the 4th number in each quantity (7 and 8). At this point in the sums, Quantity B is 4 greater than Quantity A. . . . Compare the 48th number in each quantity (195 and 196). At this point in the sums, Quantity B is 98 greater than Quantity A. Compare the 49th number in each quantity (197 and 198). At this point in the sums, Quantity B is 99 greater than Quantity A.

At this point, Quantity B is 99 greater than Quantity A. HOWEVER, we have now run out of numbers in Quantity B. Yet we still have the number 199 left to add to Quantity A. When we add this last value (199) to Quantity A, we help overcome the lead that Quantity B previously had, making Quantity A the bigger quantity.

Answer: A

RELATED VIDEO (I cover the strategy of comparing in parts starting at 2:16)

_________________

Brent Hanneson – Creator of greenlighttestprep.com If you enjoy my solutions, you'll like my GRE prep course. Sign up for GRE Question of the Dayemails

Re: The sum of the odd/even integers [#permalink]
18 May 2018, 09:08

2

This post received KUDOS

Just make a shorter range of numbers to do that easier, for example from 1 to 11 and from 2 to 10, the idea is the same, or even better. From 1 to 5 and from 2 to 4, even the last number 5 is higher than 4, and you have one more number.

Re: The sum of the odd/even integers [#permalink]
10 May 2020, 05:33

1

This post received KUDOS

Expert's post

That's a perfectly valid solution, @Farina
_________________

Brent Hanneson – Creator of greenlighttestprep.com If you enjoy my solutions, you'll like my GRE prep course. Sign up for GRE Question of the Dayemails