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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # The sum of the multiples of 4 less than 100 or The sum of  Question banks Downloads My Bookmarks Reviews Important topics
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Senior Manager Joined: 20 May 2014
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The sum of the multiples of 4 less than 100 or The sum of [#permalink] 00:00

Question Stats: 73% (01:02) correct 26% (01:05) wrong based on 104 sessions
 Quantity A Quantity B The sum of the multiples of 4 less than 100 The sum of the multiples of 5 less than 100

(A) The quantity in Column A is greater
(B) The quantity in Column B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given

Kudos for correct solution.
[Reveal] Spoiler: OA Director Joined: 03 Sep 2017
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
3
KUDOS
We can proceed by steps:

1) number of elements in the two sets: we have to take the first and the last multiple, then compute last - first, divide by the number whose multiples are of interest and sum 1. In our case, in column A, we have $$\frac{100-4}{4}+1 = 25$$, while for column B we get $$\frac{100-5}{5}+1 = 20$$.

2) Compute the sum. The formula for the sum of an arithmetic progression is $$sum = \frac{n}{2}(first+last)$$, where n is the number of elements in the progression and first and last are the first and the last elements. Thus, for column A, $$\frac{25}{2}(4+100) = 1300$$, while column B equates $$\frac{20}{2}(5+100) = 1050$$.

We conclude that A is greater!
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
Bunuel wrote:
 Quantity A Quantity B The sum of the multiples of 4 less than 100 The sum of the multiples of 5 less than 100

(A) The quantity in Column A is greater
(B) The quantity in Column B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given

Kudos for correct solution. Intern  Joined: 04 May 2017
Posts: 36
Followers: 0

Kudos [?]: 29  , given: 6

Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
1
KUDOS
Sum of multiples of 4 = 4(1+2+..+25)=4*(25+1)*25/2=50*26

Sum of multiples of 5 = 5(1+2+..+20)=5*(1+20)*20/2=50*21

-> QA > QB -> A.
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Do not pray for an easy life, pray for the strength to endure a difficult one - Bruce Lee Manager Joined: 27 Feb 2017
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
2
KUDOS
IlCreatore wrote:
We can proceed by steps:

1) number of elements in the two sets: we have to take the first and the last multiple, then compute last - first, divide by the number whose multiples are of interest and sum 1. In our case, in column A, we have $$\frac{100-4}{4}+1 = 25$$, while for column B we get $$\frac{100-5}{5}+1 = 20$$.

2) Compute the sum. The formula for the sum of an arithmetic progression is $$sum = \frac{n}{2}(first+last)$$, where n is the number of elements in the progression and first and last are the first and the last elements. Thus, for column A, $$\frac{25}{2}(4+100) = 1300$$, while column B equates $$\frac{20}{2}(5+100) = 1050$$.

We conclude that A is greater!

Hi, for step 1, is there a simplified formula that is easier to remember for exam?
Also, it says less that 100, so shouldnt we consider multiples less than 100? Like is 100 still included?

And thanks for the explanation btw
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
it should be given that multiples are of what kind...positive or negative,and inclusive or exclusive....
Retired Moderator Joined: 07 Jun 2014
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
Expert's post
ragini123 wrote:
it should be given that multiples are of what kind...positive or negative,and inclusive or exclusive....

Multiples are always considered as positive unless explicitly mentioned.

Less than 100 means that 100 should not be considered for calculation in this case.
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
2
KUDOS
IlCreatore wrote:
We can proceed by steps:

1) number of elements in the two sets: we have to take the first and the last multiple, then compute last - first, divide by the number whose multiples are of interest and sum 1. In our case, in column A, we have $$\frac{100-4}{4}+1 = 25$$, while for column B we get $$\frac{100-5}{5}+1 = 20$$.

2) Compute the sum. The formula for the sum of an arithmetic progression is $$sum = \frac{n}{2}(first+last)$$, where n is the number of elements in the progression and first and last are the first and the last elements. Thus, for column A, $$\frac{25}{2}(4+100) = 1300$$, while column B equates $$\frac{20}{2}(5+100) = 1050$$.

We conclude that A is greater!

I doubt the above explanation, kindly provide some feed back.

As we need to find the multiples of 4 & 5 less than 100, i.e. 100 exclusive

QTY A :: since the number has to be less than 100

The number of terms = $$\frac{96-4}{4}+1 = 24$$ ( last multiple of 4, less than 100 - first multiple of 4 )

The average = $$\frac{{99 + 1}}{2} = 50$$

Hence the multiples of 4 less than 100 = 50 * 24

QTY B::

The number of terms = $$\frac{95-5}{5}+1 = 19$$

The average = $$\frac{{99 + 1}}{2} = 50$$

Hence the multiples of 5 less than 100 = 50 * 19

Therefore QTY A > QTY B
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Intern Joined: 27 Jun 2019
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
pranab01 wrote:
IlCreatore wrote:
We can proceed by steps:

1) number of elements in the two sets: we have to take the first and the last multiple, then compute last - first, divide by the number whose multiples are of interest and sum 1. In our case, in column A, we have $$\frac{100-4}{4}+1 = 25$$, while for column B we get $$\frac{100-5}{5}+1 = 20$$.

2) Compute the sum. The formula for the sum of an arithmetic progression is $$sum = \frac{n}{2}(first+last)$$, where n is the number of elements in the progression and first and last are the first and the last elements. Thus, for column A, $$\frac{25}{2}(4+100) = 1300$$, while column B equates $$\frac{20}{2}(5+100) = 1050$$.

We conclude that A is greater!

I doubt the above explanation, kindly provide some feed back.

As we need to find the multiples of 4 & 5 less than 100, i.e. 100 exclusive

QTY A :: since the number has to be less than 100

The number of terms = $$\frac{96-4}{4}+1 = 24$$ ( last multiple of 4, less than 100 - first multiple of 4 )

The average = $$\frac{{99 + 1}}{2} = 50$$

Hence the multiples of 4 less than 100 = 50 * 24

QTY B::

The number of terms = $$\frac{95-5}{5}+1 = 19$$

The average = $$\frac{{99 + 1}}{2} = 50$$

Hence the multiples of 5 less than 100 = 50 * 19

Therefore QTY A > QTY B

I got the same! Intern Joined: 11 Aug 2020
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
1
KUDOS
We know that: Sum of integers from 1 to n is (n)(n+1)/2

Quantity A = Sum of multiples of 4 till 100
= 4 + 8 + 12 ...... 96 + 100
= 4*(1 + 2 + 3 ...... 24 + 25)
= 4*(25)(25+1)/2
= 4*25*13 (divided 26 by 2)
= 1300

Quantity B = Sum of multiples of 5 till 100
= 5 + 10 + 15 ...... 95 + 100
= 5*(1 + 2 + 3 ...... 19 + 20)
= 5*(20)(20+1)/2
= 5*10*21 (divided 20 by 2)
= 1050

So, A > B
Intern Joined: 07 Sep 2020
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Re: The sum of the multiples of 4 less than 100 or The sum of [#permalink]
but n/2[2a+(n-1)d] is also valid? but why i am not getting right answer? Re: The sum of the multiples of 4 less than 100 or The sum of   [#permalink] 07 Sep 2020, 07:40
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