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The sum of n numbers is greater than 48. If the average (ari [#permalink]
Expert's post 00:00

Question Stats: 100% (00:59) correct 0% (00:00) wrong based on 5 sessions
The sum of n numbers is greater than 48. If the average (arithmetic mean) of the n numbers is 1.2, what is the least possible value of n?

[Reveal] Spoiler: OA
41

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Re: The sum of n numbers is greater than 48. If the average (ari [#permalink]
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Expert's post
Carcass wrote:
The sum of n numbers is greater than 48. If the average (arithmetic mean) of the n numbers is 1.2, what is the least possible value of n?

[Reveal] Spoiler: OA
41

Average of the n numbers = (sum of n numbers)/n

Let's see what happens when the sum EQUALS 48
We get: 1.2 = 48/n
In this case, n = 40 (since 48/40 = 1.2)

However, the question tells us that the sum of the n numbers is greater than 48
So, x CANNOT equal 40
In fact, x must be greater than 40
So, the least possible value of n is 41

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com  Manager Joined: 02 Jan 2018
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Re: The sum of n numbers is greater than 48. If the average (ari [#permalink]
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48/n=1.2
n=40
Therefore >40
Which implies 41 is the answer. Re: The sum of n numbers is greater than 48. If the average (ari   [#permalink] 23 Jan 2018, 11:16
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