Average of the n numbers = (sum of n numbers)/n

Let's see what happens when the sum EQUALS 48
We get: 1.2 = 48/n
In this case, n = 40 (since 48/40 = 1.2)

However, the question tells us that the sum of the n numbers is greater than 48
So, n CANNOT equal 40
In fact, n must be greater than 40
So, the least possible value of n is 41

Cheers,
Brent
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48/n=1.2
n=40
Therefore >40
Which implies 41 is the answer.

If prompt changes from "sum of the numbers" to the sum of 'INTEGERS' then what would be the correct answer?
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Changing the question to feature "the sum of INTEGERS," would make the question super tricky.
We can still use part of the logic I used in my solution (above) to conclude that n must be greater than 40.

However, the answer will no longer be 41. Here's why:
We know that: (sum of n integers)/n = 1.2
This means we can write: sum of n integers = 1.2n
Since the sum of n INTEGERS must be an INTEGER, it must be the case that 1.2n = some INTEGER.

1.2(41) = 49.2 (NOT an integer), so, n can't equal 41
1.2(42) = 50.4 (NOT an integer), so, n can't equal 41
1.2(43) = 51.6 (NOT an integer), so, n can't equal 41
1.2(44) = 52.8 (NOT an integer), so, n can't equal 41
1.2(45) = 54 (integer!), so, n can equal 45

Answer: 45
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