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The seventh number in a sequence of numbers is 13 and each

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The seventh number in a sequence of numbers is 13 and each [#permalink] New post 09 Aug 2019, 05:34
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The seventh number in a sequence of numbers is \(31\) and each number after the first number in the sequence is \(4\) less than the number immediately preceding it. What is the fourth number in the sequence?

A. \(15\)
B. \(19\)
C. \(35\)
D. \(43\)
E. \(51\)
[Reveal] Spoiler: OA
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Re: The seventh number in a sequence of numbers is 13 and each [#permalink] New post 09 Aug 2019, 05:36
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Re: The seventh number in a sequence of numbers is 13 and each [#permalink] New post 09 Aug 2019, 07:04
Expert's post
As seventh number is 31 and each number is 4 less than the immediate previous number:

• Sixth number = 31 + 4 = 35
• Fifth number = 35 + 4 = 39
• Fourth number = 39 + 4 = 43

Hence, the correct answer is option D.

This is a GMAT question. You should use only GRE material, though.

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Re: The seventh number in a sequence of numbers is 13 and each [#permalink] New post 09 Aug 2019, 09:01
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huda wrote:
The seventh number in a sequence of numbers is \(31\) and each number after the first number in the sequence is \(4\) less than the number immediately preceding it. What is the fourth number in the sequence?

A. \(15\)
B. \(19\)
C. \(35\)
D. \(43\)
E. \(51\)


GIVEN: term7 = 31

Each number after the first number in the sequence is 4 LESS than the number immediately PRECEDING it.

This means, term8 = 31 - 4 = 27
And term9 = 27 - 4 = 23
And term10 = 23 - 4 = 19
And so on.

This also tells us that each term is 4 GREATER than the number immediately FOLLOWING it.
So, for example, term6 = 31 + 4 = 35
And term5 = 35 + 4 = 39
And term4 = 39 + 4 = 43

Answer: D

Cheers,
Brent
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Re: The seventh number in a sequence of numbers is 13 and each   [#permalink] 09 Aug 2019, 09:01
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