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# The seventh number in a sequence of numbers is 13 and each

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Director
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The seventh number in a sequence of numbers is 13 and each [#permalink]  09 Aug 2019, 05:34
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Question Stats:

61% (00:36) correct 38% (00:30) wrong based on 21 sessions
The seventh number in a sequence of numbers is $$31$$ and each number after the first number in the sequence is $$4$$ less than the number immediately preceding it. What is the fourth number in the sequence?

A. $$15$$
B. $$19$$
C. $$35$$
D. $$43$$
E. $$51$$
[Reveal] Spoiler: OA

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Director
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Kudos [?]: 102 [0], given: 161

Re: The seventh number in a sequence of numbers is 13 and each [#permalink]  09 Aug 2019, 05:36
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Re: The seventh number in a sequence of numbers is 13 and each [#permalink]  09 Aug 2019, 07:04
Expert's post
As seventh number is 31 and each number is 4 less than the immediate previous number:

• Sixth number = 31 + 4 = 35
• Fifth number = 35 + 4 = 39
• Fourth number = 39 + 4 = 43

Hence, the correct answer is option D.

This is a GMAT question. You should use only GRE material, though.

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Re: The seventh number in a sequence of numbers is 13 and each [#permalink]  09 Aug 2019, 09:01
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Expert's post
huda wrote:
The seventh number in a sequence of numbers is $$31$$ and each number after the first number in the sequence is $$4$$ less than the number immediately preceding it. What is the fourth number in the sequence?

A. $$15$$
B. $$19$$
C. $$35$$
D. $$43$$
E. $$51$$

GIVEN: term7 = 31

Each number after the first number in the sequence is 4 LESS than the number immediately PRECEDING it.

This means, term8 = 31 - 4 = 27
And term9 = 27 - 4 = 23
And term10 = 23 - 4 = 19
And so on.

This also tells us that each term is 4 GREATER than the number immediately FOLLOWING it.
So, for example, term6 = 31 + 4 = 35
And term5 = 35 + 4 = 39
And term4 = 39 + 4 = 43

Cheers,
Brent
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Re: The seventh number in a sequence of numbers is 13 and each   [#permalink] 09 Aug 2019, 09:01
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