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Intern Joined: 10 Jun 2018
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the point (-1,0) lies on the parabola [#permalink] 00:00

Question Stats: 33% (00:59) correct 66% (00:50) wrong based on 30 sessions
Attachment: geometry compare 008.jpg [ 12.03 KiB | Viewed 1528 times ]

Consider the following parabola symmetric along x axis

the point (-1,0) lies on the parabola

 Quantity A Quantity B $$x$$ $$-y^2+1$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

Last edited by Carcass on 17 Sep 2019, 04:40, edited 1 time in total.
Edited by Carcass
Intern Joined: 10 Jun 2018
Posts: 32
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Kudos [?]: 21 , given: 4

Re: the point (-1,0) lies on the parabola [#permalink]
Someone please explain the question. This is one of the questions in test set. Moderator  Joined: 07 Jan 2018
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Re: the point (-1,0) lies on the parabola [#permalink]
1
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NixonDutt wrote:
Someone please explain the question. This is one of the questions in test set.

The question is not complete. Put up a complete question. Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Re: the point (-1,0) lies on the parabola [#permalink]
1
KUDOS
Expert's post
Explanation Here we have been given a parabola symmetric along x axis.

General Equation of parabola is : $$y^2=ax+b$$ So rewrititng this equation in the form of quantities we can say:

$$x=\frac{1}{a}y^2 -\frac{b}{a}$$

Hence the two qty are equal when $$a=-1$$ and $$\frac{b}{a}=-1$$ or $$b=1$$

Now in order to calculate two variables namely $$a$$ and $$b$$ we need two eaquations. We can get one equation by putting the point (-1, 0) in the parabola equation $$y^2=ax+b$$. Hence we cannot say if the answer is C or not!

Depending upon the second point of the parabola the quantities may or maynot be equal.

_________________

Sandy
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Director Joined: 09 Nov 2018
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Re: the point (-1,0) lies on the parabola [#permalink]
amorphous wrote:
NixonDutt wrote:
Someone please explain the question. This is one of the questions in test set.

The question is not complete. Put up a complete question.

I think, as the question is not complete, answer is nothing but D.
Senior Manager Joined: 17 Aug 2019
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Re: the point (-1,0) lies on the parabola [#permalink]
sandy wrote:
Explanation Here we have been given a parabola symmetric along x axis.

General Equation of parabola is : $$y^2=ax+b$$ So rewrititng this equation in the form of quantities we can say:

$$x=\frac{1}{a}y^2 -\frac{b}{a}$$

Hence the two qty are equal when $$a=-1$$ and $$\frac{b}{a}=-1$$ or $$b=1$$

Now in order to calculate two variables namely $$a$$ and $$b$$ we need two eaquations. We can get one equation by putting the point (-1, 0) in the parabola equation $$y^2=ax+b$$. Hence we cannot say if the answer is C or not!

Depending upon the second point of the parabola the quantities may or maynot be equal.

Hello,
a=-1 did you assume it because it is facing the left ?

Next, the parabola equation if it was sym. on the y axis is $$y^2=a(x-h)+K$$ , while k and h are vertex points. Can we say for the parabola symmetric to x-axis that it is $$x^2=a(y-h)+K$$? Re: the point (-1,0) lies on the parabola   [#permalink] 17 Sep 2019, 03:37
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