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the point (-1,0) lies on the parabola

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Intern
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the point (-1,0) lies on the parabola [#permalink] New post 06 Sep 2018, 18:14
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Question Stats:

33% (00:59) correct 66% (00:35) wrong based on 9 sessions
Consider the following parabola symmetric along x axis

the point (-1,0) lies on the parabola

Quantity A
Quantity B
\(x\)
\(-y^2+1\)
[Reveal] Spoiler: OA

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Intern
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Joined: 10 Jun 2018
Posts: 32
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Kudos [?]: 14 [0], given: 4

Re: the point (-1,0) lies on the parabola [#permalink] New post 06 Sep 2018, 18:15
Someone please explain the question. This is one of the questions in test set.
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Re: the point (-1,0) lies on the parabola [#permalink] New post 07 Sep 2018, 09:21
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NixonDutt wrote:
Someone please explain the question. This is one of the questions in test set.

The question is not complete. Put up a complete question.
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Re: the point (-1,0) lies on the parabola [#permalink] New post 07 Sep 2018, 15:27
Expert's post
Explanation

Image

Here we have been given a parabola symmetric along x axis.

General Equation of parabola is : \(y^2=ax+b\) So rewrititng this equation in the form of quantities we can say:

\(x=\frac{1}{a}y^2 -\frac{b}{a}\)

Hence the two qty are equal when \(a=-1\) and \(\frac{b}{a}=-1\) or \(b=1\)

Now in order to calculate two variables namely \(a\) and \(b\) we need two eaquations. We can get one equation by putting the point (-1, 0) in the parabola equation \(y^2=ax+b\). Hence we cannot say if the answer is C or not!

Depending upon the second point of the parabola the quantities may or maynot be equal.

Hence D is the answer.
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Re: the point (-1,0) lies on the parabola   [#permalink] 07 Sep 2018, 15:27
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