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The number of zeros at the end of m when written in integer form

The number of zeros at the end of n when written in integer form

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Re: The number of zeros at the end of m when written in integer [#permalink]
05 Oct 2017, 18:01

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can be written as m = 2^16 3^17 4^17 5^16 4 5^3 n = 2^16 3^17 4^17 5^16 3 2^3 now we see in first 4 terms are same for both m and n but it m we see 5^3 * 4 that means two more zeroes thats why quantity a is greater

Re: The number of zeros at the end of m when written in integer [#permalink]
09 Oct 2017, 22:17

1

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the number of zeroes will be determined by the number of 5s and 2s. since 5*2 gives us one zero, the number of zeroes will be the number of (5*2) that we get. So in first case it is 19 and in second case it is 16. Hence A is greater than B.

Re: The number of zeros at the end of m when written in integer [#permalink]
21 Mar 2018, 12:12

Answer: A The parameters that can produce 0 are 2 and 5. n= 2^19 * 3^18 * 4^17 * 5^16 = 2^16 * 5^16 * 3^18 * 4^17 (there are 16 2s and 16 5s, we didn’t consider 4 because there are only 16 5s, if there were more than 19 5s we used 4s after 2s. So there are 16 zeros in the end of n) m= 2^16 * 3^17 * 4 ^18 * 5^19= 5^19 * 2^52 * 3^17 = 5^19 * 2^19 * 2^33 * 3^17 (there are 19 multiplication of 2 with 5. So there are 19 zeros in the end of m) So the number of zeros in m are more than n. And the answer is A. _________________

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Re: The number of zeros at the end of m when written in integer
[#permalink]
21 Mar 2018, 12:12