arc601 wrote:

Sandy,

I'm sure your answer is right, but it's not clear to me why we wouldn't find the percentage difference instead of finding the percentage change. I was looking at mathisfun's page on Percentage Difference and on it was the following passage:

"When Should it be Used?

Percentage Difference is used when both values mean the same kind of thing (for example the heights of two people).

But if there is an old value and a new value, we should use Percentage Change

Or if there is an approximate value and an exact value, we should use Percentage Error

"

To me it seems like we are comparing two values of the same type, like height, not finding a change. So, it seems like percentage difference would make more sense. It's obviously wrong as the answer I got for percentage difference is not even close to one of the available answers. So, my question is why? Why does it make more sense to use percentage change in this case?

As Carcass pointed out the key factor for evaluating percentages is the

Base.

I.E. the denominator of the fraction. Now whenever there is time line in the question the old value is in the denominator and and the new value is in the numerator.

It is very important to understand this concept. Percentages are not your friend.

For example, lets say You have 10kg of Orange which is 99 percent water by weight. They have been outside for a few days and some water evaporated so now they are 98% water by weight. What is the weight of oranges?

Some people would calculate.

The weight of Orange = 10kg weight of water= 9.9 kg.

New weight of water = 9.8 kg

However, this is wrong. because 98% water is based on new weight of oranges.

The correct way to solve this is finding the new weight of oranges. Say \(x\) amount of water get evaporated from 10 kgs of oranges.

\(\frac{9.9 -x}{10 -x}= 0.98\) or

\(9.9 - x = 9.8 - 0.98x\) or

\(9.9-9.8=0.02x\) or

\(x= 5\)

So for one percent change in mass of water the amount of water evaporated is 5 ks half of the entire orange.

_________________

Sandy

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