ExplanationThe number of students must be divisible by 10, 12, and 16. So the question is really asking, “What is the least common multiple of 10, 12, and 16?” Since all of the answer choices end in 0, each is divisible by 10.

Just use the calculator to test which choices are also divisible by 12 and 16.

Because the question asks for the minimum, start by checking the smallest choices. Since \(\frac{120}{16}\) and \(\frac{160}{12}\) are not integers, the smallest choice that works is 240.

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Sandy

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