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The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
27 May 2018, 09:29
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Question Stats:
58% (00:53) correct
41% (01:11) wrong based on 136 sessions
Quantity A 
Quantity B 
The number of days between May 30, 1917, and May 15, 1996, inclusive 
The number of days between May 15, 1912, and May 30, 1991, inclusive 
A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.
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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
17 Jul 2018, 08:57
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Let us start with quantity A The counting begins on May 1917 and ends on May 15 1996 For the time being let us consider the year in totality without computation for months.Total no of years would come to be \(1996  1917 = 19 +1 = 80\) years since both years are included.Now, Among these years let us compute the no of leap yearswhich would be \(\frac{9620}{4}+ 1 = 20\) leap years. Hence we have for qty A \(60\) normal years and \(20\) leap years and let us not forget that counting begins on may 30 and ends on may 15 so we are short of 15 days as well.Therefore qty \(A = 365* 60 + 366 *20  15\) Coming to qty B similar process as for qty A leads us to the following findings: leap years = 20 normal years = 60 and the counting begins on may 15 and ends on may 30 so we add 15 more days. Therefore qty \(B = 365 * 60 + 20 * 366 + 15\) Qty A = \(21900 + 7320  15 = 29205\) Qty B = \(22265 + 6954 + 15 = 29235\)
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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
06 Sep 2018, 12:22
amorphous wrote: Let us start with quantity A
The counting begins on May 1917 and ends on May 15 1996 For the time being let us consider the year in totality without computation for months.
Total no of years would come to be \(1996  1917 = 19 +1 = 80\) years since both years are included. Now, Among these years let us compute the no of leap years which would be \(\frac{9620}{4}+ 1 = 20\) leap years. Hence we have for qty A \(60\) normal years and \(20\) leap years and let us not forget that counting begins on may 30 and ends on may 15 so we are short of 15 days as well.
Therefore qty \(A = 365* 60 + 366 *20  15\)
Coming to qty B similar process as for qty A leads us to the following findings:
leap years = 20 normal years = 60 and the counting begins on may 15 and ends on may 30 so we add 15 more days.
Therefore qty \(B = 365 * 60 + 20 * 366 + 15\) Qty A = \(21900 + 7320  15 = 29205\) Qty B = \(22265 + 6954 + 15 = 29235\) Could you please explain how did you calculate the leap year.



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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
06 Sep 2018, 19:04
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Leap yrs are those yrs that are divisible by 4. However those yrs which can be divisible by 4 as well as 100 are not leap yrs. on top of that if any year is divisible by 4 and 100 as well as 400 it is a leap year. Posted from my mobile device
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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
22 Mar 2019, 18:04
how did found 9620 by 4



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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
22 Mar 2019, 21:50
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In qty A 1920 is the first leap yr and 1996 is the last leap yr. Hence 19961920 which is essentially 9620. Since the difference between each leap yr is 4 so we divide by 4 Posted from my mobile device
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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
06 Oct 2019, 12:45
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There is a quicker approach. A) From 19961917=79 years + from May 30  May 15 (15 days less to become a full year/350days) = 79 years and 350 days B) From 19911912=79 years + from May 15  May 30 (15 days more after becoming a full year/380days) = 79 years and 380 days Therefore quantity B is bigger. No need to calculate leap years!



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Re: The number of days between May 30, 1917, and May 15, 1996, i [#permalink]
24 Oct 2019, 22:40
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A > 79 years  15 days B > 79 years + 15 days
Hence, B is greater and it is the Answer.




Re: The number of days between May 30, 1917, and May 15, 1996, i
[#permalink]
24 Oct 2019, 22:40





