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The number 3072 is divisible by both 6 and 8. Which one of t

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The number 3072 is divisible by both 6 and 8. Which one of t [#permalink] New post 30 May 2018, 01:21
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The number 3072 is divisible by both 6 and 8. Which one of the following is the first integer larger than 3072 that is also divisible by both 6 and 8?

(A) 3078

(B) 3084

(C) 3086

(D) 3090

(E) 3096
[Reveal] Spoiler: OA

Last edited by Carcass on 30 May 2018, 15:53, edited 1 time in total.
Edited by Carcass
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Re: The number 3072 is divisible by both 6 and 8. Which one of t [#permalink] New post 31 May 2018, 11:06
Expert's post
As we are informed that number 3072 is divisible by 6 and 8.

So clearly the number \(3072+6=3078\) would be divisible by 6 and \(3072+8=3080\) are divisible by 8.

However 3080 is not divisible by 6 and 3078 is not by 8. So we need to find a number m , such that \(3072 +m\) which is divisible by 6 and 8.

m is the least common multiple of 6 and 8 . LCM of 6 and 8 is 24.

Hence the number greater than 3072 and divisible by 8 and 6 is \(24+3072=3096\).
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Re: The number 3072 is divisible by both 6 and 8. Which one of t   [#permalink] 31 May 2018, 11:06
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The number 3072 is divisible by both 6 and 8. Which one of t

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