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# The microcurrent through the electrode in a delicate circuit

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Senior Manager
Joined: 20 May 2014
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The microcurrent through the electrode in a delicate circuit [#permalink]  20 Nov 2017, 11:43
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The microcurrent through the electrode in a delicate circuit is usually held constant at $$3.6*10^{(-8)}$$ amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?

A. $$3.6 * 10^{(-8000)}$$

B. $$3.6 * 10^{(-24)}$$

C. $$3.6 * 10^{(-11)}$$

D. $$3.6 * 10^{(-5)}$$

E. $$3.6 * 10^{(-\frac{8}{3})}$$

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[Reveal] Spoiler: OA
Director
Joined: 07 Jan 2018
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Re: The microcurrent through the electrode in a delicate circuit [#permalink]  14 Jan 2018, 02:39
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The microcurrent is usually held at 3.6*10^{(-8)} however this has to be reduced by 1000 times or 10^3
If we multiply 3.6*10^{(-8)} by 10^3 we get 3.6*10^{(-5)} which is bigger than the original number not smaller
so we have to multiply 3.6*10^{(-8)} by 10^{(-3)}
(c)
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Intern
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Re: The microcurrent through the electrode in a delicate circuit [#permalink]  25 Jan 2018, 07:08
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Just divide the given equation 3.6*(1e-8) by 1.000 (or 10³) to get 3.6*(1e-11).
-> Answer C is correct
Re: The microcurrent through the electrode in a delicate circuit   [#permalink] 25 Jan 2018, 07:08
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# The microcurrent through the electrode in a delicate circuit

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