ExplanationLets assume length of rectangle A is x and width of rectangle A is y.

Clearly area of rectangle A = \(x \times y\)

Now, length of rectangle B is 10 percent less than the length of rectangle A

length of rectangle B = 0.9 x

width of rectangle B is 10 percent greater than the width of rectangle A

width of rectangle B = 1.1 y

Clearly area of rectangle B \(= 0.9 x \times 1.1 y = 0.99 \times x \times y\).

Irrespective of values of x and y (which can only be positive real numbers), Quantity A is always greater.

Hence option A is correct.
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Sandy

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