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Founder  Joined: 18 Apr 2015
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The length of rectangle B is 10 percent less than the length [#permalink]
Expert's post 00:00

Question Stats: 70% (00:45) correct 29% (01:17) wrong based on 68 sessions

The length of rectangle B is 10 percent less than the length of rectangle A, and the width of rectangle B is 10 percent greater than the width of rectangle A.

 Quantity A Quantity B The area of rectangle A The area of rectangle B

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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GRE Prep Club Legend  Joined: 07 Jun 2014
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GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Re: The length of rectangle B is 10 percent less than the length [#permalink]
Expert's post
Explanation

Lets assume length of rectangle A is x and width of rectangle A is y.

Clearly area of rectangle A = $$x \times y$$

Now, length of rectangle B is 10 percent less than the length of rectangle A

length of rectangle B = 0.9 x

width of rectangle B is 10 percent greater than the width of rectangle A

width of rectangle B = 1.1 y

Clearly area of rectangle B $$= 0.9 x \times 1.1 y = 0.99 \times x \times y$$.

Irrespective of values of x and y (which can only be positive real numbers), Quantity A is always greater.

Hence option A is correct.
_________________

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Intern Joined: 21 Apr 2019
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Re: The length of rectangle B is 10 percent less than the length [#permalink]
but if we assume area of B is xy then what happened?
Founder  Joined: 18 Apr 2015
Posts: 7386
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Kudos [?]: 1448 , given: 6583

Re: The length of rectangle B is 10 percent less than the length [#permalink]
Expert's post
Not sure what did you mean .........

regards
_________________ Re: The length of rectangle B is 10 percent less than the length   [#permalink] 29 Apr 2019, 05:24
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