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The lenghts of two sides of a triangle are 7 and 11 [#permalink]
08 Jul 2017, 13:13

1

This post received KUDOS

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Question Stats:

75% (00:29) correct
25% (00:24) wrong based on 4 sessions

Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:

The lengths of two sides of a triangle are 7 and 11

Quantity A

Quantity B

The length of the third side

4

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

My first thought was to use Pythagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.

Re: Triangle Problem [#permalink]
08 Jul 2017, 14:10

2

This post received KUDOS

Expert's post

MateusLima30 wrote:

Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:

"The lenghts of two sides of a triangle are 7 and 11."

Quantity A --> The lenght of the third side Quantity B --> 4

My first thought was to use Pitagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.

Thank!

IMPORTANT RULE: If two sides of a triangle have lengths A and B, then . . . DIFFERENCE between A and B < length of third side < SUM of A and B

So, for this question, we get: 11 - 7 < third side < 11 + 7 In other words: 4 < third side < 11

Since the 3rd side must be greater than 4, the correct answer is A

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