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The last digit of the positive even number n equals the last

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The last digit of the positive even number n equals the last [#permalink] New post 20 Apr 2018, 11:25
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60% (00:34) correct 40% (01:05) wrong based on 5 sessions
The last digit of the positive even number n equals the last digit of \(n^2\) . Which one of the following could be n ?

(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
[Reveal] Spoiler: OA

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Re: The last digit of the positive even number n equals the last [#permalink] New post 08 May 2018, 04:04
what kind of question is this..completely went bouncer.
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Re: The last digit of the positive even number n equals the last [#permalink] New post 08 May 2018, 11:47
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You should stay calm and apply techniques useful for your goal.

If you use the answer choices to reach the solution the question is easy.

The stem says an even positive number so C and E are suddenly out.

Now n must match the last digit of \(n^2\)

12 = 144 ---- 2 and four. does not fit

14 = 196 ----- 4 and 6. does not match

16 = 4.096 ----- 6 and 6. Match. D is the answer.

You could recognize that \(6^2\) is always a number that ends in 6.

Hope this helps

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Re: The last digit of the positive even number n equals the last [#permalink] New post 08 May 2018, 19:43
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I just made a careless mistake on the easiest question. Even though i read the question thouroughly and properly, while looking at answer choices, I completely forgot the 'even number' part and selected C
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Re: The last digit of the positive even number n equals the last [#permalink] New post 09 May 2018, 05:08
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kruttikaaggarwal wrote:
I just made a careless mistake on the easiest question. Even though i read the question thouroughly and properly, while looking at answer choices, I completely forgot the 'even number' part and selected C



No problem :) GRE is all about learning from our mistakes and not repeating them, I can understand.
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Re: The last digit of the positive even number n equals the last [#permalink] New post 09 May 2018, 05:13
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Carcass wrote:
You should stay calm and apply techniques useful for your goal.

If you use the answer choices to reach the solution the question is easy.

The stem says an even positive number so C and E are suddenly out.

Now n must match the last digit of \(n^2\)

12 = 144 ---- 2 and four. does not fit

14 = 196 ----- 4 and 6. does not match

16 = 4.096 ----- 6 and 6. Match. D is the answer.

You could recognize that \(6^2\) is always a number that ends in 6.

Hope this helps

Regards


Thank you for your reply.. Now I have understood it .. the wording of this question was a bit tricky for me, I should have looked at the answer choices however.
Re: The last digit of the positive even number n equals the last   [#permalink] 09 May 2018, 05:13
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