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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # The ﬁgure above shows the graph of the function f deﬁned by  Question banks Downloads My Bookmarks Reviews Important topics
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Founder  Joined: 18 Apr 2015
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The ﬁgure above shows the graph of the function f deﬁned by [#permalink]
Expert's post 00:00

Question Stats: 59% (00:36) correct 40% (01:27) wrong based on 27 sessions
Attachment: #GREpracticequestion The ﬁgure above shows the graph of the function.jpg [ 13.11 KiB | Viewed 1221 times ]

The ﬁgure above shows the graph of the function $$f$$ deﬁned by $$f(x) = |2x| + 4$$ for all numbers x. For which of the following functions $$g$$, $$f(x)$$ deﬁned for all numbers x, does the graph of $$g$$ intersect the graph of $$f$$ ?

A. $$g(x) = x − 2$$

B. $$g(x) = x + 3$$

C. $$g(x) = 2x − 2$$

D. $$g(x) = 2x + 3$$

E. $$g(x) = 3x − 2$$

Practice Questions
Question: 3
Page: 118
Difficulty: medium
[Reveal] Spoiler: OA

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Founder  Joined: 18 Apr 2015
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Kudos [?]: 1709 , given: 7477

Re: The ﬁgure above shows the graph of the function f deﬁned by [#permalink]
Expert's post
Explanation

Quote:
You can see that all ﬁve choices are linear functions whose graphs are lines with various slopes and y-intercepts. The graph of Choice A is a line with slope 1 and y-intercept −2. It is clear that this line will not intersect the graph of f to the left of the y-axis. To the right of the y-axis, the graph of f is a line with slope 2, which is greater than slope 1. Consequently, as the value of x increases, the value of y increases faster for f than for g, and therefore the graphs do not intersect to the right of the y-axis. Choice B is similarly ruled out. Note that if the y-intercept of either of the lines in Choices A and B were greater than or equal to 4 instead of less than 4, they would intersect the graph of f. Choices C and D are lines with slope 2 and y-intercepts less than 4. Hence, they are parallel to the graph of f (to the right of the y-axis) and therefore will not intersect it. Any line with a slope greater than 2 and a y-intercept less than 4, like the line in Choice E, will intersect the graph of f (to the right of the y-axis).

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Re: The ﬁgure above shows the graph of the function f deﬁned by [#permalink]
I took it for a little more difficult problem, with f(g(x)) to be checked if intersecting the f(x) graph GRE Instructor Joined: 10 Apr 2015
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Re: The ﬁgure above shows the graph of the function f deﬁned by [#permalink]
1
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Expert's post
Carcass wrote:
Attachment:
#GREpracticequestion The ﬁgure above shows the graph of the function.jpg

The ﬁgure above shows the graph of the function $$f$$ deﬁned by $$f(x) = |2x| + 4$$ for all numbers x. For which of the following functions $$g$$, $$f(x)$$ deﬁned for all numbers x, does the graph of $$g$$ intersect the graph of $$f$$ ?

A. $$g(x) = x − 2$$

B. $$g(x) = x + 3$$

C. $$g(x) = 2x − 2$$

D. $$g(x) = 2x + 3$$

E. $$g(x) = 3x − 2$$

Practice Questions
Question: 3
Page: 118
Difficulty: medium

--------------------------
ASIDE: Some students may be unfamiliar with the above format.
The most common way to define a line or curve is to write y = some expression involving x (e.g., y = 2x - 5)
Just know that graphing the equation y = 2x - 5, is the same as graphing the function f(x) = 2x - 5

Likewise, graphing the function f(x) = |2x|+ 4 is the SAME as graphing the equation y = |2x|+ 4
--------------------------

Let's first find the slope of one of the arms of the graph.

To do so, let's find 2 points that lie on the graph.

f(0) = |2(0)|+ 4
= |0|+ 4
= 4
So, when x = 0, y = 4
(0, 4) is one point.

f(1) = |2(1)|+ 4
= |2|+ 4
= 6
So, when x = 1, y = 6
(1, 6) is another point.

Apply the slope formula to get: slope = (6 - 4)/(1-0) = 2/1 = 2
So, the slope of the red arm is 2 At this point, we might see that the graphs for answer choices C and D both have slope 2.
We know this because each is written in slope y-intercept form

For example, g(x) = 2x - 2 (aka y = 2x - 2) represents a line with slope 2 and a y-intercept of -2
Likewise, g(x) = 2x + 3 represents a line with slope 2 and a y-intercept of 3

Since both lines have the same slope of the red arm of our graph, they are PARALLEL with the red arm.
This means neither line will ever intersect the graph of f ELIMINATE C and D

Now notice that the graphs for answer choices A and B both have slope 1.
That is, g(x) = x - 2 (aka y = 1x - 2) represents a line with slope 1 and a y-intercept of -2
And g(x) = x + 3 represents a line with slope 1 and a y-intercept of 3
Since both lines have a slope that's LESS THAN 2, both lines will diverge away from the red arm.
So, neither line will ever intersect the graph of f ELIMINATE A and B

By the process of elimination, the correct answer is E, but let's check it out for "fun"
The graph for answer choice E (y = 3x - 2) has slope 3.
Since the slope of y = 3x - 2 is steeper than the red arm of the graph, we know that the lines will intersect at some point. Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Day emails Re: The ﬁgure above shows the graph of the function f deﬁned by   [#permalink] 08 Jun 2019, 08:38
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