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The greatest possible value of [#permalink]
07 Dec 2017, 03:06

Expert's post

00:00

Question Stats:

80% (01:13) correct
20% (00:39) wrong based on 30 sessions

Quantity A

Quantity B

The greatest possible value of \(\frac{2}{x-y}\) where x and y are integers and \(9 \leq x \leq 12\) and \(-2 \leq y \leq 8\)

2

A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal D. The relationship cannot be determined from the information given.

Re: The greatest possible value of [#permalink]
17 Feb 2018, 01:32

Maximum value of Quantity A will be obtained if we put least possible value of x-y in denominator. That will be minimum value of x and maximum of y. Hence, Choice C is correct.
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Re: The greatest possible value of [#permalink]
03 Nov 2018, 17:30

1

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I'm sorry to revive an old topic but I disagree with the answer. What if X = 8.5 and Y = 8? The difference would be 1/2 = 0.5, which would duplicate the value of A, making it bigger than B. Is there something Im missing?

Re: The greatest possible value of [#permalink]
03 Nov 2018, 22:12

Expert's post

RCDMC wrote:

I'm sorry to revive an old topic but I disagree with the answer. What if X = 8.5 and Y = 8? The difference would be 1/2 = 0.5, which would duplicate the value of A, making it bigger than B. Is there something Im missing?

Yes you are correct. A could be actually infinity in the present state as it is NOT given that x and y are integers..

Carcass wrote:

Quantity A

Quantity B

The greatest possible value of \(\frac{2}{x-y}\) where \(9 \leq x \leq 12\) and \(-2 \leq y \leq 8\)

2

say x is 9 and y is 8.999999, \(\frac{2}{x-y}=\frac{2}{9-8.999999}=\frac{2}{0.000001}=2*10^6\), way bigger than B

So editing to make it correct.. Now when we take them as integers we take minimum value of x as 9 and maximum value of y as 8 \(A=\frac{2}{x-y}=\frac{2}{9-8}=\frac{2}{1}=2=B\)
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