chetan2u wrote:
RCDMC wrote:
I'm sorry to revive an old topic but I disagree with the answer.
What if X = 8.5 and Y = 8?
The difference would be 1/2 = 0.5, which would duplicate the value of A, making it bigger than B.
Is there something Im missing?
Yes you are correct.
A could be actually infinity in the present state as it is NOT given that x and y are integers..
Carcass wrote:
Quantity A |
Quantity B |
The greatest possible value of \(\frac{2}{x-y}\) where \(9 \leq x \leq 12\) and \(-2 \leq y \leq 8\) |
2 |
say x is 9 and y is 8.999999, \(\frac{2}{x-y}=\frac{2}{9-8.999999}=\frac{2}{0.000001}=2*10^6\), way bigger than B
So editing to make it correct..
Now when we take them as integers we take minimum value of x as 9 and maximum value of y as 8
\(A=\frac{2}{x-y}=\frac{2}{9-8}=\frac{2}{1}=2=B\)
Please check that −2≤y≤8 means max value for y is 8 not even 8.000.......001, let alone 8.9999999, and
again for x, min vale is 9 because 9≤x≤12.
As a result, 2/(9-8)=2/1=2.
Answer is C.
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Please let me know if I am wrong.