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# The greatest possible value of 3/x-y, where

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The greatest possible value of 3/x-y, where [#permalink]  27 Nov 2019, 11:07
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Question Stats:

53% (00:40) correct 46% (00:47) wrong based on 15 sessions
 Quantity A Quantity B The greatest possible value of $$\frac{3}{x-y}$$, where $$6 \leq x \leq 8$$ and $$0 \leq y \leq 5$$ $$3$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: The greatest possible value of 3/x-y, where [#permalink]  27 Nov 2019, 12:26
The answer is C.
To get greatest value of A, x-y has to be the least. To minimize x-y, we have to select lowest x-value and greatest y-value.
A=3/(6-5) = 3
So A and B are equal.
Re: The greatest possible value of 3/x-y, where   [#permalink] 27 Nov 2019, 12:26
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# The greatest possible value of 3/x-y, where

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