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# The following chart shows the employee breakdown, number of

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Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 7

Kudos [?]: 35 [0], given: 219

The following chart shows the employee breakdown, number of [#permalink]  11 Oct 2017, 22:08
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5% (low)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
The following chart shows the employee breakdown, number of marketer vs. number of programmers, at six similarly sized companies in a particular internet market. All six have similar sized management teams that are not displayed: all the non-management employees are displayed.
1) At Pindar, there are approximately how many more programmers than marketers?

(A) 6

(B) 22

(C) 35

(D) 57

(E) 73

[Reveal] Spoiler: OA
B

2) At Jericho, approximately what percent of the non-management employees are marketers?

(A) 28%

(B) 42%

(C) 51%

(D) 66%

(E) 72%

[Reveal] Spoiler: OA
E

3) If were to take the average number of marketers at five of the companies, excluding Fermion, then this average would be approximately how many employees larger than if Fermion were included in the average?

(A) 6

(B) 13

(C) 20

(D) 26

(E) 33

[Reveal] Spoiler: OA
A

[Reveal] Spoiler:
Attachment:

Employee-Breakdowns-Six-Companies.jpg [ 27.69 KiB | Viewed 237 times ]

Kudos for correct solution.
Director
Joined: 03 Sep 2017
Posts: 522
Followers: 0

Kudos [?]: 225 [1] , given: 66

Re: The following chart shows the employee breakdown, number of [#permalink]  15 Oct 2017, 01:11
1
KUDOS
Q1: The number of marketers is around 35, while the number of programmers can be computed as 93-35 = 58. Then, there are 58-35 = 23 more marketers. Among the choice, the nearest is 22 (B)

Q2: The marketers are 67 out of 93, thus approximately 67/93*100 = 72%. (E)

Q3: The mean without Fermion is roughly 50.5, while including Fermion it becomes 45. Thus it decreases of approximately 6 points (A)
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