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# The figure above represents a triangular field.

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The figure above represents a triangular field. [#permalink]  14 Oct 2017, 15:04
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Question Stats:

100% (01:52) correct 0% (00:00) wrong based on 4 sessions

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The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?

[Reveal] Spoiler: OA
60

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Re: The figure above represents a triangular field. [#permalink]  14 Oct 2017, 20:47
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Carcass wrote:

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The attachment traingle.jpg is no longer available

The figure above represents a triangular field. What is the minimum distance, in meters, that a person would have to walk to go from point A to a point on side BC?

[Reveal] Spoiler: OA
60

Here the two sides AB and AC are equal, so we can conclude that

the$${\triangle} ABC$$ is isosceles.

Now the minimum length from A to BC will be the perpendicular line.

Since the $${\triangle} ABC$$ is isosceles and perpendicular line from A to BC will meet at the midpoint D (as shown in the figure)

Now consider the $${\triangle} ABD$$

AB = 100 , BD =80 and we need to find AD

Using Pythagoras theorem

AD = $$\sqrt{(10000 - 6400)}$$ = 60

or we can see that the sides of $${\triangle} ABD$$ are in the ratio 3:4:5

= 60:80:100

Ans = 60
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Re: The figure above represents a triangular field.   [#permalink] 14 Oct 2017, 20:47
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