It is currently 10 Jul 2020, 03:46
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

The figure above represents a semicircular garden that is en

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 12020
Followers: 254

Kudos [?]: 3001 [0], given: 11253

CAT Tests
The figure above represents a semicircular garden that is en [#permalink] New post 06 Dec 2019, 02:15
Expert's post
00:00

Question Stats:

34% (00:53) correct 65% (00:55) wrong based on 29 sessions
Attachment:
#greprepclub The figure above represents a semicircular garden.jpg
#greprepclub The figure above represents a semicircular garden.jpg [ 23.49 KiB | Viewed 702 times ]


The figure above represents a semicircular garden that is enclosed by 20 feet of fencing and a straight garden wall. What is the area, in square feet, of the garden?

A. \(\frac{20}{\pi}\)

B. \(\frac{50}{\pi}\)

C. \(\frac{100}{\pi}\)

D. \(\frac{200}{\pi}\)

E. \(\frac{400}{\pi}\)


Kudos for the right answer and explanation
[Reveal] Spoiler: OA

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos
GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests.

1 KUDOS received
Intern
Intern
Joined: 03 Oct 2019
Posts: 11
Followers: 0

Kudos [?]: 9 [1] , given: 0

Re: The figure above represents a semicircular garden that is en [#permalink] New post 09 Dec 2019, 00:56
1
This post received
KUDOS
D. Double the circumference of the semi-circle. So that's 40 feet. Equate to the formula of circumference and solve for d. That's 40/π. Divide by 2 to get the radius 20/π. Apply the formula for area since you now know the radius. Note that this is for the whole circle, divide by 2 to get for the semicircle.
Manager
Manager
User avatar
Joined: 10 Feb 2020
Posts: 213
Followers: 1

Kudos [?]: 53 [0], given: 118

CAT Tests
Re: The figure above represents a semicircular garden that is en [#permalink] New post 14 Jun 2020, 05:26
Please solve this
_________________

Ever Tried? Ever Failed? No Matter. Try Again. Fail Again. Fail Better!!

1 KUDOS received
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 12020
Followers: 254

Kudos [?]: 3001 [1] , given: 11253

CAT Tests
Re: The figure above represents a semicircular garden that is en [#permalink] New post 14 Jun 2020, 09:25
1
This post received
KUDOS
Expert's post
Circumference = \(2πr
\)

Half of circumference is 20. So full circumference is 40.

Therefore:

\(2πr=40\)

=> \(πr=\frac{40}{2}\)

=> \(πr=20\)

=> \(r=\frac{20}{π}\)

Area of the garden

\(\frac{(πr^2)}{2}\)

= \(\frac{(π (\frac{20}{π}) (\frac{20}{π}))}{2} = \frac{(\frac{400}{π})}{2} = \frac{200}{π}\) Option D
_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos
GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests.

Re: The figure above represents a semicircular garden that is en   [#permalink] 14 Jun 2020, 09:25
Display posts from previous: Sort by

The figure above represents a semicircular garden that is en

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.