Carcass wrote:
Attachment:
xy.jpg
The equation of the line graphed on the rectangular XY plane above is:
\(y=\frac{8x}{9} + 3\)
Quantity A |
Quantity B |
PO |
RO |
Key concept #1: The point where a line intersects the x-axis will have a y-coordinate of 0
Key concept #2: The point where a line intersects the y-axis will have an x-coordinate of 0 Point R is the x-intercept.
So, according to Key concept #1, the y-coordinate of point R is
0To find the corresponding x-coordinate, we'll plug
y = 0 into the given equation to get:
0 = 8x/9 + 3
Subtract 3 from both sides of the equation to get: -3 = 8x/9
Multiply both sides of the equation by 9 to get: -27 = 8x
Divide both sides by 8 to get: x = -27/8
So the coordinates of point R are (-27/8,
0), which means RO =
27/8Point P is the y-intercept.
So, according to Key concept #2, the x-coordinate of point R is
0To find the corresponding y-coordinate, we'll plug
x = 0 into the given equation to get: y = 8(
0)/9 + 3
Evaluate to get: y = 3
So the coordinates of point P are (
0, 3), which means PO =
3We get:
QUANTITY A:
3QUANTITY B:
27/8Answer: B
Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.comSign up for GRE Question of the Day emails