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The digits of a two-digit number x differ by 4.

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The digits of a two-digit number x differ by 4. [#permalink] New post 21 Apr 2018, 08:25
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Question Stats:

80% (00:32) correct 20% (00:00) wrong based on 5 sessions
The digits of a two-digit number x differ by 4.

Quantity A
Quantity B
The positive difference between
the squares of the digits of x
15


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for the right explanation and solution
[Reveal] Spoiler: OA

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Re: The digits of a two-digit number x differ by 4. [#permalink] New post 21 Apr 2018, 08:46
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We are given that the digits of two digit number differ by 4.

Lets quickly visualize few numbers that satisfies this condition so that we get started!

The number could be one among 40, 15 , 51, 26, 62, 37, 73, 48, 84, 59, 95

Qty A : The positive difference between the squares of the digits of x

For example,
If we take x as 40:
Positive difference between the squares of the digits = 4^2 - 0^2 = 16

If we take x as 15:
Positive difference between the squares of the digits = |1^2 - 5^2| = 24

As you can see, the positive difference between the squares of the digits will keep on increasing if you take few more examples.

So, even the smallest possible value for Qty A (i.e.16) is greater than Qty B (15)

Correct Answer: Option A

Hope this helps :)
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Re: The digits of a two-digit number x differ by 4.   [#permalink] 21 Apr 2018, 08:46
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