IlCreatore wrote:

My solution is: since we now that the circumference of the circle is 7/8 the perimeter of the square, we can set 2*pi*r=7/8*4*l, from which we can derive that r = 7/(4*pi)*l. Then the area of a square is l^2, whereas the area of a circle is pi*r^2, where we can substitute r as above. Then, we have to compare l^2 to 49/(16*pi)*l^2 and since 49/16*pi is less than one, the area of the square is greater. So answer should be A. Why B?

OE

**Quote:**

Because the circumference of a circle depends on π(C = πd), it is best to pick values for the square. If the side of the square is 2, the perimeter is 4(2) = 8 and the area is (2)(2) = 4. Then, circumference of the circle is \(\frac{7}{8} * 8 =7\) Since circumference is 2πr = 7, the radius of the circle is r = 7/2π

Quantity A: The area of the square = 4.

Quantity B: The area of the circle = πr^2 = π (7/2π)^2 = π (7/2π)^2 = π (49/4π^2)= 49/4 π= about 3.9

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