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# The buyer of a certain mechanical toy must choose 2 of 4 opt

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The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink]  27 Jul 2018, 09:19
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100% (00:34) correct 0% (00:00) wrong based on 2 sessions
The buyer of a certain mechanical toy must choose 2 of 4 optional motions and 4 of 5 optional accessories. How many different combinations of motions and accessories are available to the buyer?

(A) 8

(B) 11

(C) 15

(D) 20

(E) 30
[Reveal] Spoiler: OA

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Joined: 20 Apr 2016
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Re: The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink]  27 Jul 2018, 09:58
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Carcass wrote:
The buyer of a certain mechanical toy must choose 2 of 4 optional motions and 4 of 5 optional accessories. How many different combinations of motions and accessories are available to the buyer?

(A) 8

(B) 11

(C) 15

(D) 20

(E) 30

So the total combination : $$4C2 * 5C2 = \frac{4 * 3}{2}* 5 = 30$$
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Re: The buyer of a certain mechanical toy must choose 2 of 4 opt   [#permalink] 27 Jul 2018, 09:58
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