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The buyer of a certain mechanical toy must choose 2 of 4 opt

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The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink] New post 27 Jul 2018, 09:19
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Question Stats:

75% (00:46) correct 25% (01:12) wrong based on 24 sessions
The buyer of a certain mechanical toy must choose 2 of 4 optional motions and 4 of 5 optional accessories. How many different combinations of motions and accessories are available to the buyer?

(A) 8

(B) 11

(C) 15

(D) 20

(E) 30
[Reveal] Spoiler: OA

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Re: The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink] New post 27 Jul 2018, 09:58
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Carcass wrote:
The buyer of a certain mechanical toy must choose 2 of 4 optional motions and 4 of 5 optional accessories. How many different combinations of motions and accessories are available to the buyer?

(A) 8

(B) 11

(C) 15

(D) 20

(E) 30



So the total combination : \(4C2 * 5C2 = \frac{4 * 3}{2}* 5 = 30\)
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Re: The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink] New post 01 Jun 2020, 12:58
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pranab223 wrote:
Carcass wrote:
The buyer of a certain mechanical toy must choose 2 of 4 optional motions and 4 of 5 optional accessories. How many different combinations of motions and accessories are available to the buyer?

(A) 8

(B) 11

(C) 15

(D) 20

(E) 30



So the total combination : \(4C2 * 5C2 = \frac{4 * 3}{2}* 5 = 30\)



It's 5 C 4. Your solution is wrong but your answer is a lucky, but correct, guess.

Right solution is

4C2 * 5C4 = (4*3)/(2*1) times (5*4*3*2)/(4*3*2*1) = 6 times 5 = 30
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Re: The buyer of a certain mechanical toy must choose 2 of 4 opt [#permalink] New post 08 Jun 2020, 07:08
The question is not in the OG Big book
Re: The buyer of a certain mechanical toy must choose 2 of 4 opt   [#permalink] 08 Jun 2020, 07:08
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