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The average price of a home County X is 250,000. The average

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The average price of a home County X is 250,000. The average [#permalink] New post 24 Oct 2017, 01:02
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80% (00:27) correct 20% (00:41) wrong based on 15 sessions
The average price of a home County X is 250,000. The average price of a home in County Y is 300,000. The average price of a home in both County X and Y is 265,000.


Quantity A
Quantity B
The number homes in County X
The number homes in County Y


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


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[Reveal] Spoiler: OA
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Re: The average price of a home County X is 250,000. The average [#permalink] New post 25 Oct 2017, 07:59
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The information above can be translated into \(\frac{250,000x + 300,000y}{x+y} = 265,000\). Solving we get \(x = \frac{7}{3}y\). Since 7/3 is greater than 1, x is greater than y.

Answer A
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Re: The average price of a home County X is 250,000. The average [#permalink] New post 02 Mar 2018, 07:13
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problem of average weight.

as the combine average is flip towards the average of x hence the no. of homes in QA are greater
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Re: The average price of a home County X is 250,000. The average [#permalink] New post 02 Mar 2018, 19:54
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With a glance in the average of two counties, we consider the average is nearer to county X so it's number of houses are more while it has more influence on the average.
also:
average = X * 250000 + Y * 300000 / (X + Y ) = 265000
so:X * 250000 + Y * 300000 = X * 265000 + Y * 265000
35000Y = 15000X
so X is bigger.
A is correct.
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Re: The average price of a home County X is 250,000. The average [#permalink] New post 04 Mar 2018, 01:02
IlCreatore wrote:
The information above can be translated into \(\frac{250,000x + 300,000y}{x+y} = 265,000\). Solving we get \(x = \frac{7}{3}y\). Since 7/3 is greater than 1, x is greater than y.

Answer A



good one, especially the 7/3 > x part
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Re: The average price of a home County X is 250,000. The average   [#permalink] 04 Mar 2018, 01:02
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