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The average of six consecutive integers in increasing order

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The average of six consecutive integers in increasing order [#permalink] New post 07 Nov 2019, 22:38
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50% (02:06) correct 50% (00:00) wrong based on 4 sessions
The average of six consecutive integers in increasing order of size is \(9\frac{1}{2}\). What is the average of the last three integers?

(A) 8

(B) \(9\frac{1}{2}\)

(C) 10

(D) 11

(E) 19
[Reveal] Spoiler: OA
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Re: The average of six consecutive integers in increasing order [#permalink] New post 08 Nov 2019, 04:07
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Expert's post
The avreage is 9.5

since the integers are consecutive they could be also all equal and at most 6

3*6=18 and the average is 9.5

D must be the answer without further calculation
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Re: The average of six consecutive integers in increasing order   [#permalink] 08 Nov 2019, 04:07
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The average of six consecutive integers in increasing order

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