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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # The average (arithmetic mean) weight of 5 crates is 250 pou  Question banks Downloads My Bookmarks Reviews Important topics
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Founder  Joined: 18 Apr 2015
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The average (arithmetic mean) weight of 5 crates is 250 pou [#permalink]
Expert's post 00:00

Question Stats: 57% (02:49) correct 42% (01:24) wrong based on 49 sessions

The average (arithmetic mean) weight of 5 crates is 250 pounds. The 2 lightest crates weigh between 200 and 205 pounds each, inclusive, and the 2 heaviest crates weigh between 300 and 310 pounds each, inclusive. If the weight of the fifth crate is x pounds, then x is expressed by which of the following?

A) 220 ≤ x ≤ 250

B) 230 ≤ x ≤ 260

C) 240 ≤ x ≤ 270

D) 250 ≤ x ≤ 270

E) 260 ≤ x ≤ 280
[Reveal] Spoiler: OA

_________________
Director Joined: 03 Sep 2017
Posts: 520
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Kudos [?]: 368 , given: 66

Re: The average (arithmetic mean) weight of 5 crates is 250 pou [#permalink]
We need to find an interval, thus we can proceed by first computing the sum of the crates weights as mean times number, i.e. 250*5 = 1250.

Now, we can derive x at the two extremes, i.e. when the lightest and heaviest crates have the higher weight and when they have the smaller weight.

In the first case, x = 1250-2*200-2*300= 250. This is the highest value of x because we have taken the minimum weight for the other crates.
In the second one, x = 1250-2*205-2*310= 220. This is the lowest value of x.

Thus the interval is 220-250. Answer A
Intern Joined: 14 Jan 2019
Posts: 31
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Kudos [?]: 9 , given: 5

Re: The average (arithmetic mean) weight of 5 crates is 250 pou [#permalink]
To calculate the greatest possible value of X: x = 1250-(2*200-2*300)= 250
To calculate the least possible value of x = x = 1250-2*205-2*310= 220.

So answer is A Re: The average (arithmetic mean) weight of 5 crates is 250 pou   [#permalink] 10 Feb 2019, 09:30
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