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The average (arithmetic mean) of x, y, and 15 is 9.

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The average (arithmetic mean) of x, y, and 15 is 9. [#permalink] New post 20 Nov 2017, 10:59
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The average (arithmetic mean) of x, y, and 15 is 9.

Quantity A
Quantity B
Average of x and y
6


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA
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Re: The average (arithmetic mean) of x, y, and 15 is 9. [#permalink] New post 06 Jul 2019, 06:49
Expert's post
Bunuel wrote:
The average (arithmetic mean) of x, y, and 15 is 9.

Quantity A
Quantity B
Average of x and y
6


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


GIVEN: The average (arithmetic mean) of x, y, and 15 is 9

We can write: \(\frac{x+y+15}{3}=9\)

Multiply both sides by 3 to get: \(x+y+15=27\)

Subtract 15 from both sides to get: \(x+y=12\)

We get:
Quantity A: average of x and y \(= \frac{x+y}{2}= \frac{12}{2}=6\)
Quantity B: 6

Answer: C

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Re: The average (arithmetic mean) of x, y, and 15 is 9.   [#permalink] 06 Jul 2019, 06:49
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The average (arithmetic mean) of x, y, and 15 is 9.

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