It is currently 02 Jul 2020, 06:57
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

The average (arithmetic mean) of x and z is greater than y,

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 11898
Followers: 250

Kudos [?]: 2961 [0], given: 11149

CAT Tests
The average (arithmetic mean) of x and z is greater than y, [#permalink] New post 15 Nov 2019, 16:39
Expert's post
00:00

Question Stats:

75% (00:22) correct 25% (00:59) wrong based on 20 sessions
The average (arithmetic mean) of x and z is greater than y, and \(x < y < z\).


Quantity A
Quantity B
The average of x, y, and z
The median of x, y, and z



A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for the right answer and solution.
[Reveal] Spoiler: OA

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos
GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests.

GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 3503
Followers: 132

Kudos [?]: 3934 [0], given: 63

CAT Tests
Re: The average (arithmetic mean) of x and z is greater than y, [#permalink] New post 16 Nov 2019, 07:11
Expert's post
Carcass wrote:
The average (arithmetic mean) of x and z is greater than y, and \(x < y < z\).


Quantity A
Quantity B
The average of x, y, and z
The median of x, y, and z



Since \(x < y < z\), we can see that the median of the set must be y. So Quantity B = y

We have:
Quantity A: \(\frac{x + y + z}{3}\)

Quantity B: \(y\)


Multiply both quantities by 3 to get:
Quantity A: \(x + y + z\)
Quantity B: \(3y\)


Subtract \(y\) from both quantities to get
Quantity A: \(x + z\)
Quantity B: \(2y\)


GIVEN: The average (arithmetic mean) of x and z is greater than y

We can write: \(\frac{x + y}{2} > y\)

Multiply both sides of the inequality by 2 to get: \(x + y > 2y\)

Perfect! This last bit of information tells us that Quantity A must be greater

Answer: A

RELATED VIDEO FROM MY COURSE

_________________

Brent Hanneson – Creator of greenlighttestprep.com
Sign up for my free GRE Question of the Day emails
Image

Re: The average (arithmetic mean) of x and z is greater than y,   [#permalink] 16 Nov 2019, 07:11
Display posts from previous: Sort by

The average (arithmetic mean) of x and z is greater than y,

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.