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# The average (arithmetic mean) of m and n is 1 more than k

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The average (arithmetic mean) of m and n is 1 more than k [#permalink]  06 Nov 2019, 09:27
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Question Stats:

85% (00:20) correct 15% (00:18) wrong based on 20 sessions
The average (arithmetic mean) of m and n is 1 more than k

 Quantity A Quantity B $$m+n$$ $$2k+1$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
[Reveal] Spoiler: OA

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Re: The average (arithmetic mean) of m and n is 1 more than k [#permalink]  07 Nov 2019, 08:56
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Carcass wrote:
The average (arithmetic mean) of m and n is 1 more than k

 Quantity A Quantity B $$m+n$$ $$2k+1$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation

We can write: (average of m and n) $$= k + 1$$

This means: $$\frac{m+n}{2} = k + 1$$

Multiply both sides by 2 to get: $$m+n = 2k + 2$$

GIVEN:
QUANTITY A: $$m+n$$
QUANTITY B: $$2k+1$$

Replace $$m+n$$ with $$2k + 2$$ to get:
QUANTITY A: $$2k+2$$
QUANTITY B: $$2k+1$$

Subtract $$2k$$ from both quantities to get:
QUANTITY A: $$2$$
QUANTITY B: $$1$$

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

Re: The average (arithmetic mean) of m and n is 1 more than k   [#permalink] 07 Nov 2019, 08:56
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