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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # The average (arithmetic mean) of all the positive multiples  Question banks Downloads My Bookmarks Reviews Important topics
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Founder  Joined: 18 Apr 2015
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The average (arithmetic mean) of all the positive multiples [#permalink]
Expert's post 00:00

Question Stats: 74% (00:43) correct 25% (00:36) wrong based on 98 sessions

 Quantity A Quantity B The average (arithmetic mean) of all the positive multiples of 5 less than 26 The average (arithmetic mean) of all the positive multiples of 7 less than 26

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ Director Joined: 03 Sep 2017
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Kudos [?]: 361  , given: 66

Re: The average (arithmetic mean) of all the positive multiples [#permalink]
2
KUDOS
This question can be solved by computing the averages on quantity A, i.e. 5+10+15+20+25/5 = 15 and on quantity B, i.e. 7+14+21/3 = 14. Answer A.

To be even faster, one can notice that in evenly spaces sets the median and the mean coincide, so that we just have to write down the elements of each set and take the central one (since the number of elements is odd). This way we have to compare 15 and 14, thus answer A Manager Joined: 22 Feb 2018
Posts: 163
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Kudos [?]: 115  , given: 22

Re: The average (arithmetic mean) of all the positive multiples [#permalink]
1
KUDOS
A: Multiples of 5 less than 26 are: 5, 10, 15, 20, 25
As each of the values is result of a constant value to previous object in sequence, their average is: (a1 +an)/2 = (5 + 25) / 2 = 15

B: The positive multiples of 7 less than 26 are: 7, 14, 21
As each of the values is result of a constant value to previous object in sequence, their average is: (a1 +an)/2 = (7 + 21) / 2 = 14

A is bigger than B

_________________ Intern Joined: 26 Mar 2017
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Kudos [?]: 12  , given: 53

Re: The average (arithmetic mean) of all the positive multiples [#permalink]
1
KUDOS
A = 5(1+2+3+4+5)
M = 5(1+2+3+4+5) / 5 = 15

B = 7(1+2+3)
M = 7(1+2+3)/3 = 14 Re: The average (arithmetic mean) of all the positive multiples   [#permalink] 11 Dec 2018, 23:38
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