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The average (arithmetic mean) of 67, 78, x, and 101 [#permalink]
 03 Jun 2017, 02:09
Question Stats:
75% (01:00) correct
25% (00:57) wrong based on 12 sessions
Quantity A |
Quantity B |
The average (arithmetic mean) of 67, 78, x, and 101 |
The average (arithmetic mean) of 66, 79, x, and 102 |
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
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Joined: 03 Sep 2017
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Re: The average (arithmetic mean) of 67, 78, x, and 101 [#permalink]
27 Sep 2017, 04:41
The two columns can be written as \(\frac{67+78+x+101}{4}\) and \(\frac{66+79+x+102}{4}\). Using matching operations method, and after rearranging, we get column A equal to \(1+x\) and column B equal to \(2+x\), thus whatever value of X, column B is greater!
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Re: The average (arithmetic mean) of 67, 78, x, and 101
[#permalink]
27 Sep 2017, 04:41
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