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The average (arithmetic mean) of 67, 78, x, and 101

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The average (arithmetic mean) of 67, 78, x, and 101 [#permalink] New post 03 Jun 2017, 02:09
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Question Stats:

66% (00:59) correct 33% (01:09) wrong based on 6 sessions



Quantity A
Quantity B
The average (arithmetic mean) of 67, 78, x, and 101
The average (arithmetic mean) of 66, 79, x, and 102


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: The average (arithmetic mean) of 67, 78, x, and 101 [#permalink] New post 27 Sep 2017, 04:41
The two columns can be written as \(\frac{67+78+x+101}{4}\) and \(\frac{66+79+x+102}{4}\). Using matching operations method, and after rearranging, we get column A equal to \(1+x\) and column B equal to \(2+x\), thus whatever value of X, column B is greater!
Re: The average (arithmetic mean) of 67, 78, x, and 101   [#permalink] 27 Sep 2017, 04:41
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The average (arithmetic mean) of 67, 78, x, and 101

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