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The average (arithmetic mean) of 4 donations to a charity

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The average (arithmetic mean) of 4 donations to a charity [#permalink] New post 07 Jun 2016, 15:54
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Question Stats:

95% (00:39) correct 4% (00:22) wrong based on 41 sessions
The average (arithmetic mean) of 4 donations to a charity was $80. Two of the 4 donations were $90 and $60.

Quantity A
Quantity B
The average of the other 2 donations
$80


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



Practice Questions
Question: 1
Page: 118
[Reveal] Spoiler: OA

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Retired Moderator
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 145

Kudos [?]: 2282 [0], given: 393

Re: The average (arithmetic mean) of 4 donations to a charity [#permalink] New post 07 Jun 2016, 15:56
Expert's post
Explanation

The average of 4 donations is $80. However, two of the four are $90 and $60 which averaged $75

$ 75 < $80 BUT we are looking for the OTHER two quantities among the four averaged. So those other two are > $80.

A is the answer
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Re: The average (arithmetic mean) of 4 donations to a charity [#permalink] New post 29 Mar 2018, 05:10
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Average of 4 donations is 80. This means the sum of 4 numbers is 4*80 = 320.

As 2 numbers are already given, and their sum is 90+60 = 150.
So the sum of rest of the numbers is 320- 150 = 170

Average of 2 numbers , 170/2 = 85

As 85 is greater than 80, the answer is A.

*To solve this answer one thing to be remembered is the underlying concept of how averages work. Average of n number of number is sum of all the products by total number of products.

Average of 2 numbers a and b is a+b/2 .

We divided the sum with 2 because there are 2 numbers.

For 3 numbers a, b and c, average = a+b+c/3
Re: The average (arithmetic mean) of 4 donations to a charity   [#permalink] 29 Mar 2018, 05:10
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The average (arithmetic mean) of 4 donations to a charity

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